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	<title>change notation and integrate by parts</title>
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		<title>change notation and integrate by parts</title>
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		<title>Tricki</title>
		<link>http://thecooper.wordpress.com/2009/04/16/tricki/</link>
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		<pubDate>Thu, 16 Apr 2009 19:02:54 +0000</pubDate>
		<dc:creator>thecooper</dc:creator>
				<category><![CDATA[Uncategorized]]></category>

		<guid isPermaLink="false">http://thecooper.wordpress.com/2009/04/16/tricki/</guid>
		<description><![CDATA[From Gowers: the Tricki is now open for business.<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=thecooper.wordpress.com&amp;blog=3799271&amp;post=104&amp;subd=thecooper&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>From <a href="http://gowers.wordpress.com/2009/04/16/tricki-now-fully-live/">Gowers</a>: the Tricki is now <a href="http://www.tricki.org/">open for business.</a></p>
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			<media:title type="html">thecooper</media:title>
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		<title>why I am a nerd</title>
		<link>http://thecooper.wordpress.com/2009/02/14/why-i-am-a-nerd/</link>
		<comments>http://thecooper.wordpress.com/2009/02/14/why-i-am-a-nerd/#comments</comments>
		<pubDate>Sat, 14 Feb 2009 04:30:42 +0000</pubDate>
		<dc:creator>thecooper</dc:creator>
				<category><![CDATA[mild]]></category>
		<category><![CDATA[problems of existence]]></category>

		<guid isPermaLink="false">http://thecooper.wordpress.com/?p=102</guid>
		<description><![CDATA[I have a project I&#8217;m saving for when I get old and grey and unable to do real math anymore.  Let me tell you about it. My adviser, and many other folks besides, seem to have major beef with proof by contradiction.  It works, but it doesn&#8217;t advance the field.  Digging into a proof by [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=thecooper.wordpress.com&amp;blog=3799271&amp;post=102&amp;subd=thecooper&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>I have a project I&#8217;m saving for when I get old and grey and unable to do real math anymore.  Let me tell you about it.</p>
<p>My adviser, and many other folks besides, seem to have major beef with proof by contradiction.  It works, but it doesn&#8217;t advance the field.  Digging into a proof by contradiction, you&#8217;re not going to find a useful object to study.</p>
<p>But I find proofs by contradiction fascinating, and they feel quite natural to me somehow.  So I want to write a book of them.  More specifically, I want to see how many standard and/or famous proofs by contradiction can be interestingly tweaked into the ur-contradiction 0=1.   I&#8217;ll call it <em>Conjectures on the One-Element Field</em>.</p>
<p>Most blow-up arguments (like Sesum&#8217;s that I just posted about) fall into this category, as do a lot of index-theory arguments (the Hairy Ball Theorem needs its own chapter, I think).  The trick is to make the 0=1 part flow from the rest the proof, and not to be too obvious and artificial about it.</p>
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		<title>scalar curvature blowup at first singular time</title>
		<link>http://thecooper.wordpress.com/2009/02/04/scalar-curvature-blowup-at-first-singular-time/</link>
		<comments>http://thecooper.wordpress.com/2009/02/04/scalar-curvature-blowup-at-first-singular-time/#comments</comments>
		<pubDate>Wed, 04 Feb 2009 05:07:20 +0000</pubDate>
		<dc:creator>thecooper</dc:creator>
				<category><![CDATA[moderate]]></category>
		<category><![CDATA[ricci flow]]></category>
		<category><![CDATA[Šešum]]></category>

		<guid isPermaLink="false">http://thecooper.wordpress.com/?p=99</guid>
		<description><![CDATA[I just figured out that Šešum&#8217;s proof that at a Ricci flow singularity in fact works, with a slight modification, to prove that at these singularities as well. To get the proof to work in this case, I note that an inequality like is how one establishes Glickenstein&#8217;s Lemma.  If , this inequality is immediate [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=thecooper.wordpress.com&amp;blog=3799271&amp;post=99&amp;subd=thecooper&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>I just figured out that Šešum&#8217;s proof that <img src='http://s0.wp.com/latex.php?latex=Ric%5Crightarrow+%5Cinfty&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='Ric&#92;rightarrow &#92;infty' title='Ric&#92;rightarrow &#92;infty' class='latex' /> at a Ricci flow singularity in fact works, with a slight modification, to prove that <img src='http://s0.wp.com/latex.php?latex=R%5Crightarrow+%5Cinfty&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='R&#92;rightarrow &#92;infty' title='R&#92;rightarrow &#92;infty' class='latex' /> at these singularities as well.</p>
<p>To get the proof to work in this case, I note that an inequality like <img src='http://s0.wp.com/latex.php?latex=%281-%5Cepsilon%29g%28t_0%29%5Cleq+g%28t%29%5Cleq+%281%2B%5Cepsilon%29g%28t_0%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='(1-&#92;epsilon)g(t_0)&#92;leq g(t)&#92;leq (1+&#92;epsilon)g(t_0)' title='(1-&#92;epsilon)g(t_0)&#92;leq g(t)&#92;leq (1+&#92;epsilon)g(t_0)' class='latex' /> is how one establishes Glickenstein&#8217;s Lemma.  If <img src='http://s0.wp.com/latex.php?latex=%7CRic%7C%5Cleq+C&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='|Ric|&#92;leq C' title='|Ric|&#92;leq C' class='latex' />, this inequality is immediate since <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+g%3D-2Ric&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;partial_t g=-2Ric' title='&#92;partial_t g=-2Ric' class='latex' />.</p>
<p>However, we can still get such an inequality even if <img src='http://s0.wp.com/latex.php?latex=Ric&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='Ric' title='Ric' class='latex' /> isn&#8217;t bounded.  First note that, for the rescaled flows <img src='http://s0.wp.com/latex.php?latex=g_k%28t%29%3DQ_kg%28t_k%2B%5Cfrac%7Bt%7D%7B%5Csqrt%7BQ_k%7D%7D%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='g_k(t)=Q_kg(t_k+&#92;frac{t}{&#92;sqrt{Q_k}})' title='g_k(t)=Q_kg(t_k+&#92;frac{t}{&#92;sqrt{Q_k}})' class='latex' />, we have a uniform Ricci bound <img src='http://s0.wp.com/latex.php?latex=%7CRic_k%7C%5Cleq+1&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='|Ric_k|&#92;leq 1' title='|Ric_k|&#92;leq 1' class='latex' />.  So for each <img src='http://s0.wp.com/latex.php?latex=k&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='k' title='k' class='latex' /> we can choose <img src='http://s0.wp.com/latex.php?latex=t&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='t' title='t' class='latex' /> close enough to <img src='http://s0.wp.com/latex.php?latex=t_0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='t_0' title='t_0' class='latex' /> that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%281-%5Cepsilon%29g_k%28t_0%29%5Cleq+g_k%28t%29%5Cleq+%281%2B%5Cepsilon%29g_k%28t_0%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='(1-&#92;epsilon)g_k(t_0)&#92;leq g_k(t)&#92;leq (1+&#92;epsilon)g_k(t_0)' title='(1-&#92;epsilon)g_k(t_0)&#92;leq g_k(t)&#92;leq (1+&#92;epsilon)g_k(t_0)' class='latex' /></p>
<p style="text-align:left;">Here &#8216;close enough&#8217; is independent of <img src='http://s0.wp.com/latex.php?latex=k&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='k' title='k' class='latex' />.  Then, using the definition of <img src='http://s0.wp.com/latex.php?latex=g_k&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='g_k' title='g_k' class='latex' />, we see that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%281-%5Cepsilon%29g%28t_k%2B%5Cfrac%7Bt_0%7D%7B%5Csqrt%7BQ_k%7D%7D%29%5Cleq+g%28t_k%2B%5Cfrac%7Bt%7D%7B%5Csqrt%7BQ_k%7D%7D%29%5Cleq+%281%2B%5Cepsilon%29g%28t_k%2B%5Cfrac%7Bt_0%7D%7B%5Csqrt%7BQ_k%7D%7D%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='(1-&#92;epsilon)g(t_k+&#92;frac{t_0}{&#92;sqrt{Q_k}})&#92;leq g(t_k+&#92;frac{t}{&#92;sqrt{Q_k}})&#92;leq (1+&#92;epsilon)g(t_k+&#92;frac{t_0}{&#92;sqrt{Q_k}})' title='(1-&#92;epsilon)g(t_k+&#92;frac{t_0}{&#92;sqrt{Q_k}})&#92;leq g(t_k+&#92;frac{t}{&#92;sqrt{Q_k}})&#92;leq (1+&#92;epsilon)g(t_k+&#92;frac{t_0}{&#92;sqrt{Q_k}})' class='latex' /></p>
<p style="text-align:left;">So if we want to prove, for any <img src='http://s0.wp.com/latex.php?latex=s&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='s' title='s' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=s_0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='s_0' title='s_0' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=%281-%5Cepsilon%29g%28s_0%29%5Cleq+g%28s%29%5Cleq+%281%2B%5Cepsilon%29g%28s_0%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='(1-&#92;epsilon)g(s_0)&#92;leq g(s)&#92;leq (1+&#92;epsilon)g(s_0)' title='(1-&#92;epsilon)g(s_0)&#92;leq g(s)&#92;leq (1+&#92;epsilon)g(s_0)' class='latex' />, we just have to write <img src='http://s0.wp.com/latex.php?latex=s_0%3Dt_k%2B%5Cfrac%7Bt_0%7D%7B%5Csqrt%7BQ_k%7D%7D%2C+s%3Dt_k%2B%5Cfrac%7Bt%7D%7B%5Csqrt%7BQ_k%7D%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='s_0=t_k+&#92;frac{t_0}{&#92;sqrt{Q_k}}, s=t_k+&#92;frac{t}{&#92;sqrt{Q_k}}' title='s_0=t_k+&#92;frac{t_0}{&#92;sqrt{Q_k}}, s=t_k+&#92;frac{t}{&#92;sqrt{Q_k}}' class='latex' />, which can clearly be done.  In fact we just have to find one such <img src='http://s0.wp.com/latex.php?latex=t_k&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='t_k' title='t_k' class='latex' />.  So we get a Glickenstein&#8217;s Lemma for a flow with merely <img src='http://s0.wp.com/latex.php?latex=R&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='R' title='R' class='latex' /> bounded.</p>
<p style="text-align:left;">The rest of the proof works just fine, because in the limit we still get <img src='http://s0.wp.com/latex.php?latex=%5Coverline%7BR%7D%3D0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;overline{R}=0' title='&#92;overline{R}=0' class='latex' />, hence by the evolution equation</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cpartial_tR%3D%5CDelta+R%2B+%7CRic%7C%5E2&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;partial_tR=&#92;Delta R+ |Ric|^2' title='&#92;partial_tR=&#92;Delta R+ |Ric|^2' class='latex' /></p>
<p style="text-align:left;">we see that <img src='http://s0.wp.com/latex.php?latex=%5Coverline%7BRic%7D%5Cequiv+0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;overline{Ric}&#92;equiv 0' title='&#92;overline{Ric}&#92;equiv 0' class='latex' />.</p>
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		<title>Huisken and Sinestrari 2008 &#8211; II</title>
		<link>http://thecooper.wordpress.com/2009/02/01/huisken-and-sinestrari-ii/</link>
		<comments>http://thecooper.wordpress.com/2009/02/01/huisken-and-sinestrari-ii/#comments</comments>
		<pubDate>Sun, 01 Feb 2009 19:31:06 +0000</pubDate>
		<dc:creator>thecooper</dc:creator>
				<category><![CDATA[mean curvature flow]]></category>
		<category><![CDATA[moderate]]></category>

		<guid isPermaLink="false">http://thecooper.wordpress.com/?p=93</guid>
		<description><![CDATA[I already gave the broad outline of Huisken and Sinestrari&#8217;s 2008 paper; I left out several big chunks that make the whole thing work. Recall that we&#8217;re dealing with a family of 2-convex hypersurfaces evolving via mean curvature flow.  We&#8217;ll assume uniform 2-convexity, i.e. for some . I won&#8217;t go into the analytic work, but [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=thecooper.wordpress.com&amp;blog=3799271&amp;post=93&amp;subd=thecooper&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>I already gave the broad outline of Huisken and Sinestrari&#8217;s 2008 paper; I left out several big chunks that make the whole thing work.</p>
<p>Recall that we&#8217;re dealing with a family of 2-convex hypersurfaces evolving via mean curvature flow.  We&#8217;ll assume uniform 2-convexity, i.e. <img src='http://s0.wp.com/latex.php?latex=%5Clambda_1%2B%5Clambda_2%5Cgeq+%5Calpha+H&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;lambda_1+&#92;lambda_2&#92;geq &#92;alpha H' title='&#92;lambda_1+&#92;lambda_2&#92;geq &#92;alpha H' class='latex' /> for some <img src='http://s0.wp.com/latex.php?latex=%5Calpha%3E0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;alpha&gt;0' title='&#92;alpha&gt;0' class='latex' />.</p>
<p>I won&#8217;t go into the analytic work, but we need to use it.  There are two analytic results we need:</p>
<blockquote><p><strong>Cylindrical Estimate.</strong> For any <img src='http://s0.wp.com/latex.php?latex=%5Ceta%3E0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;eta&gt;0' title='&#92;eta&gt;0' class='latex' />, there exists <img src='http://s0.wp.com/latex.php?latex=C%28%5Ceta%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='C(&#92;eta)' title='C(&#92;eta)' class='latex' /> also depending on <img src='http://s0.wp.com/latex.php?latex=%5Calpha&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;alpha' title='&#92;alpha' class='latex' /> and the diameter of the initial hypersurface, so that along the flow</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%7CA%7C%5E2-%5Cfrac%7B1%7D%7Bn-1%7DH%5E2%5Cleq+%5Ceta+H%5E2%2BC%28%5Ceta%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='|A|^2-&#92;frac{1}{n-1}H^2&#92;leq &#92;eta H^2+C(&#92;eta)' title='|A|^2-&#92;frac{1}{n-1}H^2&#92;leq &#92;eta H^2+C(&#92;eta)' class='latex' /></p>
</blockquote>
<p>I call this a cylindrical estimate because the quantity <img src='http://s0.wp.com/latex.php?latex=%7CA%7C%5E2-%5Cfrac%7B1%7D%7Bn-1%7DH%5E2&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='|A|^2-&#92;frac{1}{n-1}H^2' title='|A|^2-&#92;frac{1}{n-1}H^2' class='latex' /> vanishes on a cylinder, and when <img src='http://s0.wp.com/latex.php?latex=%5Clambda_1&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;lambda_1' title='&#92;lambda_1' class='latex' /> is small it measures the sum of the squares of the differences of the higher eigenvalues.</p>
<blockquote><p><strong>Harnack Estimate.</strong> For any <img src='http://s0.wp.com/latex.php?latex=h%2Ck%5Cin+%5Cmathbb%7BN%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='h,k&#92;in &#92;mathbb{N}' title='h,k&#92;in &#92;mathbb{N}' class='latex' />, there exist <img src='http://s0.wp.com/latex.php?latex=C_1%2CC_2+%3E0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='C_1,C_2 &gt;0' title='C_1,C_2 &gt;0' class='latex' /> also depending on <img src='http://s0.wp.com/latex.php?latex=%5Calpha&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;alpha' title='&#92;alpha' class='latex' />, the initial diameter, so that along the flow</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%7C%5Cpartial_t%5Eh%5Cnabla%5EkA%7C%5Cleq+C_1+%7CA%7C%5E%7B2k%2B4h%7D%2BC_2&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='|&#92;partial_t^h&#92;nabla^kA|&#92;leq C_1 |A|^{2k+4h}+C_2' title='|&#92;partial_t^h&#92;nabla^kA|&#92;leq C_1 |A|^{2k+4h}+C_2' class='latex' /></p>
</blockquote>
<p>One first establishes these estimates for the smooth flow, and it&#8217;s rather easy to see that the surgery procedure doesn&#8217;t affect the constants, since surgery involves replacing approximate cylinders with approximate spheres.</p>
<p>Recall that the surgery procedure relies upon finding Hamilton necks&#8211;that is, regions of  the hypersurface that are approximate round cylinders.  In fact we want to do better than finding a region which looks like a cylinder at one time; we want to find regions that shrink like cylinders under the flow.</p>
<blockquote><p><strong>Definition.</strong> We call the spacetime region <img src='http://s0.wp.com/latex.php?latex=%5COmega%5Csubset+M%5Ctimes+%5Ba%2Cb%5D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;Omega&#92;subset M&#92;times [a,b]' title='&#92;Omega&#92;subset M&#92;times [a,b]' class='latex' /> an <img src='http://s0.wp.com/latex.php?latex=%28%5Cepsilon%2C+k%2C+L%2C%5Ctheta%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='(&#92;epsilon, k, L,&#92;theta)' title='(&#92;epsilon, k, L,&#92;theta)' class='latex' /> shrinking neck if</p>
<ul>
<li> The final time-slice <img src='http://s0.wp.com/latex.php?latex=%5COmega_b&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;Omega_b' title='&#92;Omega_b' class='latex' /> is a Hamilton neck  <img src='http://s0.wp.com/latex.php?latex=%5Cepsilon&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;epsilon' title='&#92;epsilon' class='latex' />-close to a round neck in <img src='http://s0.wp.com/latex.php?latex=C%5Ek&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='C^k' title='C^k' class='latex' />.  Call the approximate radius of this neck <img src='http://s0.wp.com/latex.php?latex=r_b&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='r_b' title='r_b' class='latex' />.</li>
<li><img src='http://s0.wp.com/latex.php?latex=%5COmega_t&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;Omega_t' title='&#92;Omega_t' class='latex' /> is <img src='http://s0.wp.com/latex.php?latex=%28%5Cepsilon%2Ck%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='(&#92;epsilon,k)' title='(&#92;epsilon,k)' class='latex' /> close to <img src='http://s0.wp.com/latex.php?latex=r%28t%29%5COmega_b&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='r(t)&#92;Omega_b' title='r(t)&#92;Omega_b' class='latex' />, where <img src='http://s0.wp.com/latex.php?latex=r%28t%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='r(t)' title='r(t)' class='latex' /> is the radius of a round cylinder at time <img src='http://s0.wp.com/latex.php?latex=t&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='t' title='t' class='latex' />, which shrinks to radius <img src='http://s0.wp.com/latex.php?latex=r_b&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='r_b' title='r_b' class='latex' /> at time <img src='http://s0.wp.com/latex.php?latex=b&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='b' title='b' class='latex' />.</li>
<li><img src='http://s0.wp.com/latex.php?latex=b-a%3Dr_b%5E2%5Ctheta&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='b-a=r_b^2&#92;theta' title='b-a=r_b^2&#92;theta' class='latex' />, and each neck has length <img src='http://s0.wp.com/latex.php?latex=r_bL&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='r_bL' title='r_bL' class='latex' />.</li>
</ul>
</blockquote>
<p>All of the singularity analysis resides in the following theorem:</p>
<blockquote><p><strong>Neck Detection Lemma. </strong>Let <img src='http://s0.wp.com/latex.php?latex=%5Cepsilon%2C+k%2C+L%2C%5Ctheta&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;epsilon, k, L,&#92;theta' title='&#92;epsilon, k, L,&#92;theta' class='latex' /> be constants as above.  There exist constants <img src='http://s0.wp.com/latex.php?latex=%5Ceta%5E%2A%2C+H%5E%2A&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;eta^*, H^*' title='&#92;eta^*, H^*' class='latex' /> depending on <img src='http://s0.wp.com/latex.php?latex=%5Cepsilon%2C+k%2C+L%2C%5Ctheta%2C+%5Calpha&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;epsilon, k, L,&#92;theta, &#92;alpha' title='&#92;epsilon, k, L,&#92;theta, &#92;alpha' class='latex' />, and the initial diameter, so that if any <img src='http://s0.wp.com/latex.php?latex=%28p_0%2Ct_0%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='(p_0,t_0)' title='(p_0,t_0)' class='latex' /> satisfies:</p>
<ol>
<li><img src='http://s0.wp.com/latex.php?latex=H%28p_0%2Ct_0%29%5Cgeq+H%5E%2A&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='H(p_0,t_0)&#92;geq H^*' title='H(p_0,t_0)&#92;geq H^*' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B%5Clambda_1%7D%7BH%7D%28p_0%2Ct_0%29%5Cleq+%5Ceta%5E%2A&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;frac{&#92;lambda_1}{H}(p_0,t_0)&#92;leq &#92;eta^*' title='&#92;frac{&#92;lambda_1}{H}(p_0,t_0)&#92;leq &#92;eta^*' class='latex' /></li>
<li>The parabolic neighbourhood <img src='http://s0.wp.com/latex.php?latex=P%28p_0%2Ct_0%2CL%2C%5Ctheta%29%3DB_%7Bg%28t_0%29%7D%28p_0%2C%5Cfrac%7Bn-1%7D%7BH%28p_0%29%7DL%29%5Ctimes+%5Bt_0-%28%5Cfrac%7Bn-1%7D%7BH%28p_0%29%7D%29%5E2%5Ctheta%2Ct_0%5D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='P(p_0,t_0,L,&#92;theta)=B_{g(t_0)}(p_0,&#92;frac{n-1}{H(p_0)}L)&#92;times [t_0-(&#92;frac{n-1}{H(p_0)})^2&#92;theta,t_0]' title='P(p_0,t_0,L,&#92;theta)=B_{g(t_0)}(p_0,&#92;frac{n-1}{H(p_0)}L)&#92;times [t_0-(&#92;frac{n-1}{H(p_0)})^2&#92;theta,t_0]' class='latex' /> doesn&#8217;t contain any points affect by a previous surgery.</li>
</ol>
</blockquote>
<blockquote><p>then <img src='http://s0.wp.com/latex.php?latex=P%28p_0%2Ct_0%2CL-1%2C%5Cfrac%7B%5Ctheta%7D%7B2%7D%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='P(p_0,t_0,L-1,&#92;frac{&#92;theta}{2})' title='P(p_0,t_0,L-1,&#92;frac{&#92;theta}{2})' class='latex' /> is an <img src='http://s0.wp.com/latex.php?latex=%28%5Cepsilon%2C+k%2C+L-1%2C%5Cfrac%7B%5Ctheta%7D%7B2%7D%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='(&#92;epsilon, k, L-1,&#92;frac{&#92;theta}{2})' title='(&#92;epsilon, k, L-1,&#92;frac{&#92;theta}{2})' class='latex' />-shrinking neck.</p></blockquote>
<p>To prove this theorem, we are going to argue by contradiction, using a blow-up argument.</p>
<p><strong>Proof of the Neck Detection Lemma</strong>.  If the theorem is not true, we may take a sequence of flows, <img src='http://s0.wp.com/latex.php?latex=%5C%7BM%28t%29_j%5C%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;{M(t)_j&#92;}' title='&#92;{M(t)_j&#92;}' class='latex' /> each of which contains a point <img src='http://s0.wp.com/latex.php?latex=%28p_j%2Ct_j%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='(p_j,t_j)' title='(p_j,t_j)' class='latex' /> so that <img src='http://s0.wp.com/latex.php?latex=H%28p_j%2Ct_j%29%5Crightarrow%5Cinfty%2C+%5Cfrac%7B%5Clambda_1%7D%7BH%7D%28p_j%2Ct_j%29%7D%5Crightarrow+0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='H(p_j,t_j)&#92;rightarrow&#92;infty, &#92;frac{&#92;lambda_1}{H}(p_j,t_j)}&#92;rightarrow 0' title='H(p_j,t_j)&#92;rightarrow&#92;infty, &#92;frac{&#92;lambda_1}{H}(p_j,t_j)}&#92;rightarrow 0' class='latex' /> and each parabolic neighbourhood <img src='http://s0.wp.com/latex.php?latex=P_j&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='P_j' title='P_j' class='latex' /> is unaffected by surgery, and so that none of them has <img src='http://s0.wp.com/latex.php?latex=P%28p_j%2Ct_j%2CL-1%2C%5Cfrac%7B%5Ctheta%7D%7B2%7D%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='P(p_j,t_j,L-1,&#92;frac{&#92;theta}{2})' title='P(p_j,t_j,L-1,&#92;frac{&#92;theta}{2})' class='latex' /> as a shrinking neck.</p>
<p>Rescale and translate each of the flows: to get <img src='http://s0.wp.com/latex.php?latex=%5Ctilde%7BM%7D_j%28t%29%3DH%28p_j%2Ct_j%29%5BM_j%28t_j%2B%5Cfrac%7Bt%7D%7BH%28p_j%2Ct_j%29%7D%29-p_j%5D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;tilde{M}_j(t)=H(p_j,t_j)[M_j(t_j+&#92;frac{t}{H(p_j,t_j)})-p_j]' title='&#92;tilde{M}_j(t)=H(p_j,t_j)[M_j(t_j+&#92;frac{t}{H(p_j,t_j)})-p_j]' class='latex' /> so that <img src='http://s0.wp.com/latex.php?latex=%5Ctilde%7BH%7D_j%280%2C0%29%3D1&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;tilde{H}_j(0,0)=1' title='&#92;tilde{H}_j(0,0)=1' class='latex' />.  The parabolic neighbourhoods all  rescale to the same <img src='http://s0.wp.com/latex.php?latex=%5Ctilde%7BP%7D%3D%5Ctilde%7BP%7D_j%3DP%280%2C0%2CL%2C%5Ctheta%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;tilde{P}=&#92;tilde{P}_j=P(0,0,L,&#92;theta)' title='&#92;tilde{P}=&#92;tilde{P}_j=P(0,0,L,&#92;theta)' class='latex' />.</p>
<p>Tracing the Harnack estimate,  we get a Harnack estimate for <img src='http://s0.wp.com/latex.php?latex=H&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='H' title='H' class='latex' />, so that the <img src='http://s0.wp.com/latex.php?latex=%5Ctilde%7BH%7D_j&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;tilde{H}_j' title='&#92;tilde{H}_j' class='latex' /> are bounded uniformly on <img src='http://s0.wp.com/latex.php?latex=%5Ctilde%7BP%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;tilde{P}' title='&#92;tilde{P}' class='latex' />.  Then the cylindrical estimate says that <img src='http://s0.wp.com/latex.php?latex=%5Ctilde%7BA%7D_j&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;tilde{A}_j' title='&#92;tilde{A}_j' class='latex' /> are uniformly bounded in <img src='http://s0.wp.com/latex.php?latex=%5Ctilde%7BP%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;tilde{P}' title='&#92;tilde{P}' class='latex' />.</p>
<p>Then the Harnack estimate says that in fact all derivatives of $latex\tilde{A}_j$ are uniformly bounded in <img src='http://s0.wp.com/latex.php?latex=%5Ctilde%7BP%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;tilde{P}' title='&#92;tilde{P}' class='latex' />.  So according to the Arzela-Ascoli theorem, there is a limit flow <img src='http://s0.wp.com/latex.php?latex=%5Ctilde%7BM%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;tilde{M}' title='&#92;tilde{M}' class='latex' />, with convergence in <img src='http://s0.wp.com/latex.php?latex=C%5E%7Bk%7D%28P%280%2C0%2CL-1%2C%5Cfrac%7B%5Ctheta%7D%7B2%7D%29%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='C^{k}(P(0,0,L-1,&#92;frac{&#92;theta}{2}))' title='C^{k}(P(0,0,L-1,&#92;frac{&#92;theta}{2}))' class='latex' /> where <img src='http://s0.wp.com/latex.php?latex=k&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='k' title='k' class='latex' /> is the control we have on the derivatives during surgery.</p>
<p>Consider the properties of <img src='http://s0.wp.com/latex.php?latex=%5Ctilde%7BM%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;tilde{M}' title='&#92;tilde{M}' class='latex' />. We have <img src='http://s0.wp.com/latex.php?latex=%5Ctilde%7BH%7D%280%2C0%29%3D1%2C+%5Cfrac%7B%5Ctilde%7B%5Clambda%7D_1%7D%7B%5Ctilde%7BH%7D%7D%280%2C0%29%3D0%2C+%7C%5Ctilde%7BA%7D%7C%5E2%5Cleq+%5Cfrac%7B1%7D%7Bn-1%7D%5Ctilde%7BH%7D%5E2&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;tilde{H}(0,0)=1, &#92;frac{&#92;tilde{&#92;lambda}_1}{&#92;tilde{H}}(0,0)=0, |&#92;tilde{A}|^2&#92;leq &#92;frac{1}{n-1}&#92;tilde{H}^2' title='&#92;tilde{H}(0,0)=1, &#92;frac{&#92;tilde{&#92;lambda}_1}{&#92;tilde{H}}(0,0)=0, |&#92;tilde{A}|^2&#92;leq &#92;frac{1}{n-1}&#92;tilde{H}^2' class='latex' />.</p>
<p>Now <img src='http://s0.wp.com/latex.php?latex=%5Ctilde%7B%5Clambda_1%7D%5Cgeq+0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;tilde{&#92;lambda_1}&#92;geq 0' title='&#92;tilde{&#92;lambda_1}&#92;geq 0' class='latex' />,  and <img src='http://s0.wp.com/latex.php?latex=%5Clambda_1&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;lambda_1' title='&#92;lambda_1' class='latex' /> satisfies a parabolic equation, so achieving its minimum at an interior point means in fact <img src='http://s0.wp.com/latex.php?latex=%5Ctilde%7B%5Clambda%7D_1%5Cequiv+0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;tilde{&#92;lambda}_1&#92;equiv 0' title='&#92;tilde{&#92;lambda}_1&#92;equiv 0' class='latex' />.  Then <img src='http://s0.wp.com/latex.php?latex=%7C%5Ctilde%7BA%7D%7C%5E2-%5Cfrac%7B1%7D%7Bn-1%7D%5Ctilde%7BH%7D%5E2%3D%5Csum_%7B1%3Ci%3Cj%7D%28%5Ctilde%7B%5Clambda%7D_1-%5Ctilde%7B%5Clambda%7D_j%29%5E2%5Cgeq+0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='|&#92;tilde{A}|^2-&#92;frac{1}{n-1}&#92;tilde{H}^2=&#92;sum_{1&lt;i&lt;j}(&#92;tilde{&#92;lambda}_1-&#92;tilde{&#92;lambda}_j)^2&#92;geq 0' title='|&#92;tilde{A}|^2-&#92;frac{1}{n-1}&#92;tilde{H}^2=&#92;sum_{1&lt;i&lt;j}(&#92;tilde{&#92;lambda}_1-&#92;tilde{&#92;lambda}_j)^2&#92;geq 0' class='latex' />.  So in fact <img src='http://s0.wp.com/latex.php?latex=%5Ctilde%7BA%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;tilde{A}' title='&#92;tilde{A}' class='latex' /> has a zero eigenvalue and all other eigenvalues equal.</p>
<p>The evolution equation for the quantity <img src='http://s0.wp.com/latex.php?latex=%7CA%7C%5E2-%5Cfrac%7B1%7D%7Bn-1%7DH%5E2&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='|A|^2-&#92;frac{1}{n-1}H^2' title='|A|^2-&#92;frac{1}{n-1}H^2' class='latex' /> (which we have just proved is identically zero) has a term involving <img src='http://s0.wp.com/latex.php?latex=%7C%5Cnabla+A%7C&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='|&#92;nabla A|' title='|&#92;nabla A|' class='latex' />, so we see that <img src='http://s0.wp.com/latex.php?latex=%5Cnabla+A%5Cequiv+0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;nabla A&#92;equiv 0' title='&#92;nabla A&#92;equiv 0' class='latex' />, i.e. <img src='http://s0.wp.com/latex.php?latex=A&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='A' title='A' class='latex' /> is covariant constant.  A rigidity theorem of Lawson says that this characterises cylinders.</p>
<p>Thus <img src='http://s0.wp.com/latex.php?latex=%5Ctilde%7BM%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;tilde{M}' title='&#92;tilde{M}' class='latex' /> is a shrinking cylinder on <img src='http://s0.wp.com/latex.php?latex=%5Ctilde%7BP%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;tilde{P}' title='&#92;tilde{P}' class='latex' />.  So the sequence <img src='http://s0.wp.com/latex.php?latex=%5Ctilde%7BM%7D_j%5Ccap+P%280%2C0%2CL-1%2C%5Cfrac%7B%5Ctheta%7D%7B2%7D%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;tilde{M}_j&#92;cap P(0,0,L-1,&#92;frac{&#92;theta}{2})' title='&#92;tilde{M}_j&#92;cap P(0,0,L-1,&#92;frac{&#92;theta}{2})' class='latex' /> is approaching a shrinking cylinder, hence for large enough <img src='http://s0.wp.com/latex.php?latex=j&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='j' title='j' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=%5Ctilde%7BP%7D_j&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;tilde{P}_j' title='&#92;tilde{P}_j' class='latex' /> is a shrinking neck.  But <img src='http://s0.wp.com/latex.php?latex=%5Ctilde%7BP%7D_j&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;tilde{P}_j' title='&#92;tilde{P}_j' class='latex' /> is just a rescaling of <img src='http://s0.wp.com/latex.php?latex=P_j&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='P_j' title='P_j' class='latex' />.  So <img src='http://s0.wp.com/latex.php?latex=P_j&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='P_j' title='P_j' class='latex' /> is a shrinking neck, in contradiction to our assumption.</p>
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		<title>Ricci blowup at first singular time</title>
		<link>http://thecooper.wordpress.com/2009/01/31/curvature-blowup-at-first-singular-time/</link>
		<comments>http://thecooper.wordpress.com/2009/01/31/curvature-blowup-at-first-singular-time/#comments</comments>
		<pubDate>Sat, 31 Jan 2009 20:58:34 +0000</pubDate>
		<dc:creator>thecooper</dc:creator>
				<category><![CDATA[moderate]]></category>
		<category><![CDATA[prerequisites required]]></category>
		<category><![CDATA[ricci flow]]></category>

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		<description><![CDATA[The major analytic task in geometric flows is to understand the structure of singularities.   The first step toward understanding singularities and their development under the flow is a theorem like: Characterisation of Ricci Flow Singularities.  Suppose is a Ricci flow, defined up to time .  Assume is maximal.  Then we have , where is the [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=thecooper.wordpress.com&amp;blog=3799271&amp;post=88&amp;subd=thecooper&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>The major analytic task in geometric flows is to understand the structure of singularities.   The first step toward understanding singularities and their development under the flow is a theorem like:</p>
<blockquote><p><strong>Characterisation of Ricci Flow Singularities</strong>.  Suppose <img src='http://s0.wp.com/latex.php?latex=%5C%7Bg%28t%29%5C%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;{g(t)&#92;}' title='&#92;{g(t)&#92;}' class='latex' /> is a Ricci flow, defined up to time <img src='http://s0.wp.com/latex.php?latex=T%3C%5Cinfty&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='T&lt;&#92;infty' title='T&lt;&#92;infty' class='latex' />.  Assume <img src='http://s0.wp.com/latex.php?latex=T&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='T' title='T' class='latex' /> is maximal.  Then we have <img src='http://s0.wp.com/latex.php?latex=%7C%5Cmax+Rm%28t%29%7C%5Crightarrow%5Cinfty&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='|&#92;max Rm(t)|&#92;rightarrow&#92;infty' title='|&#92;max Rm(t)|&#92;rightarrow&#92;infty' class='latex' />, where <img src='http://s0.wp.com/latex.php?latex=Rm&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='Rm' title='Rm' class='latex' /> is the Riemann tensor.</p></blockquote>
<p>That is to say, what goes wrong at a Ricci flow singularity is the curvature tensor.  We could restate the theorem as its contrapositive:</p>
<blockquote><p><strong>Characterisation of When the Flow Can Be Extended.</strong> Suppose that up to time <img src='http://s0.wp.com/latex.php?latex=t_0%3C%5Cinfty&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='t_0&lt;&#92;infty' title='t_0&lt;&#92;infty' class='latex' />, we have a bound <img src='http://s0.wp.com/latex.php?latex=%7C%5Cmax+Rm%7C%5Cleq+C%3C%5Cinfty&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='|&#92;max Rm|&#92;leq C&lt;&#92;infty' title='|&#92;max Rm|&#92;leq C&lt;&#92;infty' class='latex' />.  Then the Ricci flow can be extended past <img src='http://s0.wp.com/latex.php?latex=t_0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='t_0' title='t_0' class='latex' />.</p></blockquote>
<p>But of course the curvature tensor is a big nasty gadget, which is none too easy to understand.  We want something easier to check than &#8220;Are my curvatures all bounded?&#8221;.  Šešum proved that, in fact, one need only look at the trace of the Riemann tensor, which is the Ricci tensor:</p>
<blockquote><p><strong>Better Characterisation of Ricci Flow Singularities.</strong> As above, let <img src='http://s0.wp.com/latex.php?latex=T%3C%5Cinfty&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='T&lt;&#92;infty' title='T&lt;&#92;infty' class='latex' /> be the first singular time of a Ricci flow.  Then <img src='http://s0.wp.com/latex.php?latex=%7C%5Cmax+Ric%28t%29%7C%5Crightarrow%5Cinfty&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='|&#92;max Ric(t)|&#92;rightarrow&#92;infty' title='|&#92;max Ric(t)|&#92;rightarrow&#92;infty' class='latex' />.</p></blockquote>
<p>This is somewhat remarkable, because the Ricci tensor interacts weirdly with Ricci flow.  For example, the condition <img src='http://s0.wp.com/latex.php?latex=Ric%5Cgeq+K&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='Ric&#92;geq K' title='Ric&#92;geq K' class='latex' /> is not preserved under the flow.  Yet somehow the Ricci tensor carries the information about when singularities occur.  Proof under the fold.</p>
<p><span id="more-88"></span></p>
<p>We start with a ball-collapse estimate.  Ultimately, the estimate derives from Perel&#8217;man&#8217;s density ideas.</p>
<blockquote><p><strong>Glickenstein&#8217;s Lemma</strong>.  Let <img src='http://s0.wp.com/latex.php?latex=r%3E0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='r&gt;0' title='r&gt;0' class='latex' />.  Then we have <img src='http://s0.wp.com/latex.php?latex=B_%7Bg%280%29%7D%28x%2C+%5Cfrac%7Br%7D%7B1%2B%5Csqrt%7Be%5E%7B2Ct%7D-1%7D%7D%29%5Csubset+B_%7Bg%28t%29%7D%28x%2Cr%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='B_{g(0)}(x, &#92;frac{r}{1+&#92;sqrt{e^{2Ct}-1}})&#92;subset B_{g(t)}(x,r)' title='B_{g(0)}(x, &#92;frac{r}{1+&#92;sqrt{e^{2Ct}-1}})&#92;subset B_{g(t)}(x,r)' class='latex' />, where <img src='http://s0.wp.com/latex.php?latex=C&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='C' title='C' class='latex' /> is a bound for the Ricci tensor.</p></blockquote>
<p>That is to say, balls are collapsing at worst like <img src='http://s0.wp.com/latex.php?latex=e%5E%7BCt%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='e^{Ct}' title='e^{Ct}' class='latex' />.</p>
<p>Now suppose that we have a flow with <img src='http://s0.wp.com/latex.php?latex=%7CRic%7C%5Cleq+C&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='|Ric|&#92;leq C' title='|Ric|&#92;leq C' class='latex' />, but which has a singularity at <img src='http://s0.wp.com/latex.php?latex=T%3C%5Cinfty&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='T&lt;&#92;infty' title='T&lt;&#92;infty' class='latex' />.  We will obtain a contradiction by a blow-up argument.</p>
<p>Since <img src='http://s0.wp.com/latex.php?latex=T%3C%5Cinfty&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='T&lt;&#92;infty' title='T&lt;&#92;infty' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=Rm&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='Rm' title='Rm' class='latex' /> is blowing up, i.e. there is a sequence <img src='http://s0.wp.com/latex.php?latex=p_k%5Cin+M_%7Bt_k%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='p_k&#92;in M_{t_k}' title='p_k&#92;in M_{t_k}' class='latex' /> with <img src='http://s0.wp.com/latex.php?latex=%7CRm%28p_k%2Ct_k%29%7C%5Crightarrow%5Cinfty&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='|Rm(p_k,t_k)|&#92;rightarrow&#92;infty' title='|Rm(p_k,t_k)|&#92;rightarrow&#92;infty' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=t_k%5Crightarrow+T&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='t_k&#92;rightarrow T' title='t_k&#92;rightarrow T' class='latex' />.  Set <img src='http://s0.wp.com/latex.php?latex=Q_k%3D%7CRm%28p_k%2Ct_k%29%7C&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='Q_k=|Rm(p_k,t_k)|' title='Q_k=|Rm(p_k,t_k)|' class='latex' />.  Consider the rescaled metrics</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=g_k%28t%29%3DQ_kg%28t_k%2B%5Cfrac%7Bt%7D%7BQ_k%7D%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='g_k(t)=Q_kg(t_k+&#92;frac{t}{Q_k})' title='g_k(t)=Q_kg(t_k+&#92;frac{t}{Q_k})' class='latex' /></p>
<p>each of which is also a solution to the Ricci flow.  The pointed manifolds <img src='http://s0.wp.com/latex.php?latex=%5C%7B%28M%2Cg_k%28t%29%2Cp_k%29%5C%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;{(M,g_k(t),p_k)&#92;}' title='&#92;{(M,g_k(t),p_k)&#92;}' class='latex' /> converge to a limit <img src='http://s0.wp.com/latex.php?latex=%28%5Coverline%7BM%7D%2C%5Coverline%7Bg%7D%28t%29%2Cp%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='(&#92;overline{M},&#92;overline{g}(t),p)' title='(&#92;overline{M},&#92;overline{g}(t),p)' class='latex' /> for each <img src='http://s0.wp.com/latex.php?latex=t&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='t' title='t' class='latex' />.  By the work of Hamilton, <img src='http://s0.wp.com/latex.php?latex=%28%5Coverline%7BM%7D%2C%5Coverline%7Bg%7D%28t%29%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='(&#92;overline{M},&#92;overline{g}(t))' title='(&#92;overline{M},&#92;overline{g}(t))' class='latex' /> is an ancient solution to the Ricci flow.</p>
<p>We want to come up with more properties of <img src='http://s0.wp.com/latex.php?latex=%5Coverline%7Bg%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;overline{g}' title='&#92;overline{g}' class='latex' />.  Since <img src='http://s0.wp.com/latex.php?latex=%7CRic%28g%28t%29%29%7C%5Cleq+C&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='|Ric(g(t))|&#92;leq C' title='|Ric(g(t))|&#92;leq C' class='latex' />, we have <img src='http://s0.wp.com/latex.php?latex=R%28g%28t%29%29%5Cleq+C&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='R(g(t))&#92;leq C' title='R(g(t))&#92;leq C' class='latex' /> as well.  The rescaled scalar curvature is <img src='http://s0.wp.com/latex.php?latex=R%28g_k%28t%29%29%3D%5Cfrac%7BR%28g%28t%29%29%7D%7BQ_k%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='R(g_k(t))=&#92;frac{R(g(t))}{Q_k}' title='R(g_k(t))=&#92;frac{R(g(t))}{Q_k}' class='latex' />, and since <img src='http://s0.wp.com/latex.php?latex=Q_k%5Crightarrow+%5Cinfty&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='Q_k&#92;rightarrow &#92;infty' title='Q_k&#92;rightarrow &#92;infty' class='latex' />, we see that <img src='http://s0.wp.com/latex.php?latex=R%28%5Coverline%7Bg%7D%28t%29%29%3D0.&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='R(&#92;overline{g}(t))=0.' title='R(&#92;overline{g}(t))=0.' class='latex' /></p>
<p>Under Ricci flow, the scalar curvature evolves as <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+R%3D%5CDelta+R+%2B+2%7CRic%7C%5E2&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;partial_t R=&#92;Delta R + 2|Ric|^2' title='&#92;partial_t R=&#92;Delta R + 2|Ric|^2' class='latex' />, so the vanishing of <img src='http://s0.wp.com/latex.php?latex=R%28%5Coverline%7Bg%7D%28t%29%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='R(&#92;overline{g}(t))' title='R(&#92;overline{g}(t))' class='latex' /> implies the vanishing of <img src='http://s0.wp.com/latex.php?latex=Ric%28%5Coverline%7Bg%7D%28t%29%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='Ric(&#92;overline{g}(t))' title='Ric(&#92;overline{g}(t))' class='latex' />.  Thus <img src='http://s0.wp.com/latex.php?latex=%28%5Coverline%7BM%7D%2C%5Coverline%7Bg%7D%28t%29%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='(&#92;overline{M},&#92;overline{g}(t))' title='(&#92;overline{M},&#92;overline{g}(t))' class='latex' /> is a stationary solution to Ricci flow, i.e. <img src='http://s0.wp.com/latex.php?latex=%5Coverline%7Bg%7D%28t%29%5Cequiv+%5Coverline%7Bg%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;overline{g}(t)&#92;equiv &#92;overline{g}' title='&#92;overline{g}(t)&#92;equiv &#92;overline{g}' class='latex' />.</p>
<p>Consider the volume of a ball of radius <img src='http://s0.wp.com/latex.php?latex=r%3E0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='r&gt;0' title='r&gt;0' class='latex' /> in the limit metric:</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bvol_%7B%5Coverline%7Bg%7D%7D%28B%28p%2Cr%29%29%7D%7Br%5En%7D%3D%5Clim+%5Cfrac%7Bvol_%7Bg_k%280%7D%28B%28p_k%2Cr%29%29%7D%7Br%5En%7D%3D%5Clim+%5Cfrac%7Bvol_%7Bg%28t_k%29%7DB%28p_k%2C+%5Cfrac%7Br%7D%7B%5Csqrt%7BQ_k%7D%7D%29%7D%7B%28%5Cfrac%7Br%7D%7B%5Csqrt%7BQ_k%7D%7D%29%5En%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;frac{vol_{&#92;overline{g}}(B(p,r))}{r^n}=&#92;lim &#92;frac{vol_{g_k(0}(B(p_k,r))}{r^n}=&#92;lim &#92;frac{vol_{g(t_k)}B(p_k, &#92;frac{r}{&#92;sqrt{Q_k}})}{(&#92;frac{r}{&#92;sqrt{Q_k}})^n}' title='&#92;frac{vol_{&#92;overline{g}}(B(p,r))}{r^n}=&#92;lim &#92;frac{vol_{g_k(0}(B(p_k,r))}{r^n}=&#92;lim &#92;frac{vol_{g(t_k)}B(p_k, &#92;frac{r}{&#92;sqrt{Q_k}})}{(&#92;frac{r}{&#92;sqrt{Q_k}})^n}' class='latex' /></p>
<p style="text-align:left;">Now let <img src='http://s0.wp.com/latex.php?latex=%5Cepsilon%3E0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;epsilon&gt;0' title='&#92;epsilon&gt;0' class='latex' /> be arbitrary.  Since <img src='http://s0.wp.com/latex.php?latex=t_k%5Crightarrow+T&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='t_k&#92;rightarrow T' title='t_k&#92;rightarrow T' class='latex' />, we can choose <img src='http://s0.wp.com/latex.php?latex=k_0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='k_0' title='k_0' class='latex' /> large enough that</p>
<ul>
<li><img src='http://s0.wp.com/latex.php?latex=e%5E%7B%5Cfrac%7BC%7D%7B%5Csqrt%7Bn%7D%7D%7Ct_k-t_%7Bk_0%7D%7C%7D%3E1-%5Cfrac%7B%5Cepsilon%7D%7B2%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='e^{&#92;frac{C}{&#92;sqrt{n}}|t_k-t_{k_0}|}&gt;1-&#92;frac{&#92;epsilon}{2}' title='e^{&#92;frac{C}{&#92;sqrt{n}}|t_k-t_{k_0}|}&gt;1-&#92;frac{&#92;epsilon}{2}' class='latex' /></li>
<li><img src='http://s0.wp.com/latex.php?latex=%28%5Cfrac%7B1%7D%7B1%2B%5Csqrt%7Be%5E%7B2C%28t_%7Bk%7D-t_%7Bk_0%7D%29%7D-1%7D%7D%29%5En%3E1-%5Cfrac%7B%5Cepsilon%7D%7B2%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='(&#92;frac{1}{1+&#92;sqrt{e^{2C(t_{k}-t_{k_0})}-1}})^n&gt;1-&#92;frac{&#92;epsilon}{2}' title='(&#92;frac{1}{1+&#92;sqrt{e^{2C(t_{k}-t_{k_0})}-1}})^n&gt;1-&#92;frac{&#92;epsilon}{2}' class='latex' /></li>
<li><img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bvol%28B%28p%2Cr%29%29%7D%7Br%5En%7D%5Cgeq+%5Cfrac%7Bvol_%7Bg%28t_k%29%7D%28B%28p_k%2C%5Cfrac%7Br%7D%7B%5Csqrt%7BQ_k%7D%7D%29%29%7D%7B%28%5Cfrac%7Br%7D%7B%5Csqrt%7BQ_k%7D%7D%29%5En%7D-%5Cfrac%7B%5Cepsilon%7D%7B2%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;frac{vol(B(p,r))}{r^n}&#92;geq &#92;frac{vol_{g(t_k)}(B(p_k,&#92;frac{r}{&#92;sqrt{Q_k}}))}{(&#92;frac{r}{&#92;sqrt{Q_k}})^n}-&#92;frac{&#92;epsilon}{2}' title='&#92;frac{vol(B(p,r))}{r^n}&#92;geq &#92;frac{vol_{g(t_k)}(B(p_k,&#92;frac{r}{&#92;sqrt{Q_k}}))}{(&#92;frac{r}{&#92;sqrt{Q_k}})^n}-&#92;frac{&#92;epsilon}{2}' class='latex' /></li>
</ul>
<p>for any <img src='http://s0.wp.com/latex.php?latex=k%3Ek_0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='k&gt;k_0' title='k&gt;k_0' class='latex' />.</p>
<p>By Glickenstein&#8217;s lemma, we have <img src='http://s0.wp.com/latex.php?latex=B_%7Bg%28t_%7Bk_0%7D%29%7D%28p_k%2C+%5Cfrac%7Br%7D%7B%5Csqrt%7BQ_k%7D%281%2B%5Csqrt%7Be%5E%7B2C%28t_k-t_%7Bk_0%7D%29%7D-1%7D%7D%5Csubset+B_%7Bg%28t_k%29%7D%28p_k%2C%5Cfrac%7Br%7D%7B%5Csqrt%7BQ_k%7D%7D%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='B_{g(t_{k_0})}(p_k, &#92;frac{r}{&#92;sqrt{Q_k}(1+&#92;sqrt{e^{2C(t_k-t_{k_0})}-1}}&#92;subset B_{g(t_k)}(p_k,&#92;frac{r}{&#92;sqrt{Q_k}})' title='B_{g(t_{k_0})}(p_k, &#92;frac{r}{&#92;sqrt{Q_k}(1+&#92;sqrt{e^{2C(t_k-t_{k_0})}-1}}&#92;subset B_{g(t_k)}(p_k,&#92;frac{r}{&#92;sqrt{Q_k}})' class='latex' />.    Applying the evolution equation for the volume form, we have the estimate</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=vol_%7Bg%28t_k%29%7D%28B_%7Bg%28t_%7Bk_0%7D%29%7D%28p_k%2C+%5Cfrac%7Br%7D%7B%5Csqrt%7BQ_k%7D%281%2B%5Csqrt%7Be%5E%7B2C%28t_k-t_%7Bk_0%7D%29%7D-1%7D%7D%29%5Cgeq+%281-%5Cfrac%7B%5Cepsilon%7D%7B2%7D%29vol_%7Bg%28t_%7Bk_0%7D%29%7D%28B_%7Bg%28t_%7Bk_0%7D%29%7D%28p_k%2C%5Cfrac%7Br%7D%7B%5Csqrt%7BQ_k%7D%281%2B%5Csqrt%7Be%5E%7B2C%28t_k-t_%7Bk_0%7D%29%7D-1%7D%7D%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='vol_{g(t_k)}(B_{g(t_{k_0})}(p_k, &#92;frac{r}{&#92;sqrt{Q_k}(1+&#92;sqrt{e^{2C(t_k-t_{k_0})}-1}})&#92;geq (1-&#92;frac{&#92;epsilon}{2})vol_{g(t_{k_0})}(B_{g(t_{k_0})}(p_k,&#92;frac{r}{&#92;sqrt{Q_k}(1+&#92;sqrt{e^{2C(t_k-t_{k_0})}-1}})' title='vol_{g(t_k)}(B_{g(t_{k_0})}(p_k, &#92;frac{r}{&#92;sqrt{Q_k}(1+&#92;sqrt{e^{2C(t_k-t_{k_0})}-1}})&#92;geq (1-&#92;frac{&#92;epsilon}{2})vol_{g(t_{k_0})}(B_{g(t_{k_0})}(p_k,&#92;frac{r}{&#92;sqrt{Q_k}(1+&#92;sqrt{e^{2C(t_k-t_{k_0})}-1}})' class='latex' /></p>
<p style="text-align:left;">Thus we have fixed a single metric in the volume comparison limit:</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bvol_%7B%5Coverline%7Bg%7D%7D%28B_%7B%5Coverline%7Bg%7D%7D%28p%2Cr%29%29%7D%7Br%5En%7D%3E%281-%5Cfrac%7B%5Cepsilon%7D%7B2%7D%29%5Cfrac%7Bvol_%7Bg%28t_%7Bk_0%7D%29%7DB_%7Bg%28t_%7Bk_0%7D%29%7D%28p_k%2C+%5Cfrac%7Br%7D%7B%5Csqrt%7BQ_k%7D%281%2B%5Csqrt%7Be%5E%7B2C%28t_k-t_%7Bk_0%7D%29%7D-1%7D%7D%29%7D%7B%28%5Cfrac%7Br%7D%7B%5Csqrt%7BQ_k%7D%7D%29%5En%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;frac{vol_{&#92;overline{g}}(B_{&#92;overline{g}}(p,r))}{r^n}&gt;(1-&#92;frac{&#92;epsilon}{2})&#92;frac{vol_{g(t_{k_0})}B_{g(t_{k_0})}(p_k, &#92;frac{r}{&#92;sqrt{Q_k}(1+&#92;sqrt{e^{2C(t_k-t_{k_0})}-1}})}{(&#92;frac{r}{&#92;sqrt{Q_k}})^n}' title='&#92;frac{vol_{&#92;overline{g}}(B_{&#92;overline{g}}(p,r))}{r^n}&gt;(1-&#92;frac{&#92;epsilon}{2})&#92;frac{vol_{g(t_{k_0})}B_{g(t_{k_0})}(p_k, &#92;frac{r}{&#92;sqrt{Q_k}(1+&#92;sqrt{e^{2C(t_k-t_{k_0})}-1}})}{(&#92;frac{r}{&#92;sqrt{Q_k}})^n}' class='latex' /></p>
<p style="text-align:left;">Now recall that the scalar curvature is the quadratic term in the Taylor expansion for the volume of a ball:</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=vol_%7Bg%28k_0%29%7D%28B%28p_k%2C%5Cfrac%7Br%7D%7B%5Csqrt%7BQ_k%7D%281%2B%5Csqrt%7Be%5E%7B2C%28t_k-t_%7Bk_0%7D%29%7D-1%7D%7D%29%3D%5Comega_n%5B%5Cfrac%7Br%7D%7B%5Csqrt%7BQ_k%7D%281%2B%5Csqrt%7Be%5E%7B2C%28t_k-t_%7Bk_0%7D%29%7D-1%7D%29%7D%5D%5En%281-%5Cfrac%7BR%28g%28t_%7Bk_0%7D%29%29%7D%7B6%28n%2B2%29%7D%5Cfrac%7Br%5E2%7D%7BQ_k%281%2B%5Csqrt%7Be%5E%7B2C%28t_k-t_%7Bk_0%7D%29%7D-1%7D%29%5E2%7D%2BO%28%5B%5Cfrac%7Br%7D%7B%5Csqrt%7BQ_k%7D%281%2B%5Csqrt%7Be%5E%7B2C%28t_k-t_%7Bk_0%7D%29%7D-1%7D%29%7D%5D%5E4%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='vol_{g(k_0)}(B(p_k,&#92;frac{r}{&#92;sqrt{Q_k}(1+&#92;sqrt{e^{2C(t_k-t_{k_0})}-1}})=&#92;omega_n[&#92;frac{r}{&#92;sqrt{Q_k}(1+&#92;sqrt{e^{2C(t_k-t_{k_0})}-1})}]^n(1-&#92;frac{R(g(t_{k_0}))}{6(n+2)}&#92;frac{r^2}{Q_k(1+&#92;sqrt{e^{2C(t_k-t_{k_0})}-1})^2}+O([&#92;frac{r}{&#92;sqrt{Q_k}(1+&#92;sqrt{e^{2C(t_k-t_{k_0})}-1})}]^4)' title='vol_{g(k_0)}(B(p_k,&#92;frac{r}{&#92;sqrt{Q_k}(1+&#92;sqrt{e^{2C(t_k-t_{k_0})}-1}})=&#92;omega_n[&#92;frac{r}{&#92;sqrt{Q_k}(1+&#92;sqrt{e^{2C(t_k-t_{k_0})}-1})}]^n(1-&#92;frac{R(g(t_{k_0}))}{6(n+2)}&#92;frac{r^2}{Q_k(1+&#92;sqrt{e^{2C(t_k-t_{k_0})}-1})^2}+O([&#92;frac{r}{&#92;sqrt{Q_k}(1+&#92;sqrt{e^{2C(t_k-t_{k_0})}-1})}]^4)' class='latex' /></p>
<p style="text-align:left;">(Here <img src='http://s0.wp.com/latex.php?latex=%5Comega_n&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;omega_n' title='&#92;omega_n' class='latex' /> is the volume of a euclidean ball.) Letting <img src='http://s0.wp.com/latex.php?latex=k%5Crightarrow+%5Cinfty&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='k&#92;rightarrow &#92;infty' title='k&#92;rightarrow &#92;infty' class='latex' />, we get</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bvol%28B%28p%2Cr%29%29%7D%7Br%5En%7D%3E%281-%5Cfrac%7B%5Cepsilon%7D%7B2%7D%29%5E2%5Comega_n-%5Cepsilon&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;frac{vol(B(p,r))}{r^n}&gt;(1-&#92;frac{&#92;epsilon}{2})^2&#92;omega_n-&#92;epsilon' title='&#92;frac{vol(B(p,r))}{r^n}&gt;(1-&#92;frac{&#92;epsilon}{2})^2&#92;omega_n-&#92;epsilon' class='latex' /></p>
<p style="text-align:left;">So that in fact <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bvol%28B%28p%2Cr%29%29%7D%7Br%5En%7D%5Cgeq+%5Comega_n&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;frac{vol(B(p,r))}{r^n}&#92;geq &#92;omega_n' title='&#92;frac{vol(B(p,r))}{r^n}&#92;geq &#92;omega_n' class='latex' /> since <img src='http://s0.wp.com/latex.php?latex=%5Cepsilon%3E0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;epsilon&gt;0' title='&#92;epsilon&gt;0' class='latex' /> was arbitrary.</p>
<p style="text-align:left;">On the other hand, the Bishop-Gromov comparison says that <img src='http://s0.wp.com/latex.php?latex=Ric%5Cgeq+0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='Ric&#92;geq 0' title='Ric&#92;geq 0' class='latex' /> means  <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bvol%28B%28p%2Cr%29%29%7D%7Br%5En%7D%5Cleq+%5Comega_n&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;frac{vol(B(p,r))}{r^n}&#92;leq &#92;omega_n' title='&#92;frac{vol(B(p,r))}{r^n}&#92;leq &#92;omega_n' class='latex' />.  So <img src='http://s0.wp.com/latex.php?latex=%28N%2C%5Coverline%7Bg%7D%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='(N,&#92;overline{g})' title='(N,&#92;overline{g})' class='latex' /> has the same ball volume as euclidean space.</p>
<p style="text-align:left;">This in turn implies that <img src='http://s0.wp.com/latex.php?latex=%28N%2C%5Coverline%7Bg%7D%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='(N,&#92;overline{g})' title='(N,&#92;overline{g})' class='latex' /> is flat.  So <img src='http://s0.wp.com/latex.php?latex=Rm%28%5Coverline%7Bg%7D%29%5Cequiv+0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='Rm(&#92;overline{g})&#92;equiv 0' title='Rm(&#92;overline{g})&#92;equiv 0' class='latex' />.  But each <img src='http://s0.wp.com/latex.php?latex=%7CRm_%7Bg_k%7D%28p_k%2C0%29%7C%3D1&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='|Rm_{g_k}(p_k,0)|=1' title='|Rm_{g_k}(p_k,0)|=1' class='latex' />, so <img src='http://s0.wp.com/latex.php?latex=%7CRm%28p%2C0%29%7C%3D1&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='|Rm(p,0)|=1' title='|Rm(p,0)|=1' class='latex' />.  Thus we have the desired contradiction.</p>
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		<title>Huisken and Sinestrari 2008 &#8211; I</title>
		<link>http://thecooper.wordpress.com/2009/01/30/huisken-and-sinestrari-2008-i/</link>
		<comments>http://thecooper.wordpress.com/2009/01/30/huisken-and-sinestrari-2008-i/#comments</comments>
		<pubDate>Fri, 30 Jan 2009 07:25:47 +0000</pubDate>
		<dc:creator>thecooper</dc:creator>
				<category><![CDATA[math posts]]></category>
		<category><![CDATA[mean curvature flow]]></category>
		<category><![CDATA[moderate]]></category>
		<category><![CDATA[prerequisites required]]></category>

		<guid isPermaLink="false">http://thecooper.wordpress.com/?p=74</guid>
		<description><![CDATA[This is essentially the talk I prepared for my comprehensive exam.  It&#8217;s a bit more detailed because, unlike in real life, there are no time limits on blogs. The smooth mean curvature flow is a family of embeddings satisfying , that is, moving by its mean curvature.  For our purposes, we will consider closed (compact [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=thecooper.wordpress.com&amp;blog=3799271&amp;post=74&amp;subd=thecooper&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><em>This is essentially the talk I prepared for my comprehensive exam.  It&#8217;s a bit more detailed because, unlike in real life, there are no time limits on blogs.</em></p>
<p>The smooth mean curvature flow is a family of embeddings <img src='http://s0.wp.com/latex.php?latex=F_t%3AM%5En%5Crightarrow+R%5E%7Bn%2B1%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='F_t:M^n&#92;rightarrow R^{n+1}' title='F_t:M^n&#92;rightarrow R^{n+1}' class='latex' /> satisfying <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B%5Cpartial+F%7D%7B%5Cpartial+t%7D%3D%5Coverline%7BH%7D%3D-H%5Cnu&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;frac{&#92;partial F}{&#92;partial t}=&#92;overline{H}=-H&#92;nu' title='&#92;frac{&#92;partial F}{&#92;partial t}=&#92;overline{H}=-H&#92;nu' class='latex' />, that is, moving by its mean curvature.  For our purposes, we will consider <img src='http://s0.wp.com/latex.php?latex=M&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='M' title='M' class='latex' /> closed (compact without boundary).  I&#8217;ll be fairly cavalier about identifying the embedding <img src='http://s0.wp.com/latex.php?latex=F_t&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='F_t' title='F_t' class='latex' /> with its image <img src='http://s0.wp.com/latex.php?latex=M_t&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='M_t' title='M_t' class='latex' />.</p>
<p>Now <img src='http://s0.wp.com/latex.php?latex=H%3Dtr%28A%29%3Dg%5E%7Bij%7D%28%5Cpartial_i%5Cpartial_jF%5Ccdot%5Cnu%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='H=tr(A)=g^{ij}(&#92;partial_i&#92;partial_jF&#92;cdot&#92;nu)' title='H=tr(A)=g^{ij}(&#92;partial_i&#92;partial_jF&#92;cdot&#92;nu)' class='latex' />, and we may take normal coordinates so that <img src='http://s0.wp.com/latex.php?latex=g_%7Bij%7D%3D%5Cdelta_%7Bij%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='g_{ij}=&#92;delta_{ij}' title='g_{ij}=&#92;delta_{ij}' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_i%5Cpartial_jF&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;partial_i&#92;partial_jF' title='&#92;partial_i&#92;partial_jF' class='latex' /> is a normal vector.  In these coordinates, then, <img src='http://s0.wp.com/latex.php?latex=H%3D%5Csum_i+%5Cpartial_i%5E2F&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='H=&#92;sum_i &#92;partial_i^2F' title='H=&#92;sum_i &#92;partial_i^2F' class='latex' />.  So we may write <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_t+F%3D%5CDelta+F&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;partial_t F=&#92;Delta F' title='&#92;partial_t F=&#92;Delta F' class='latex' />, and think of the mean curvature flow as the heat equation for hypersurfaces.  In particular, the flow is parabolic, so we get maximum and comparison principles, as well as local existence and uniqueness.</p>
<p>As in the case of Ricci flow, mean curvature flow exhibits finite-time singularity development.  To see this, let <img src='http://s0.wp.com/latex.php?latex=M&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='M' title='M' class='latex' /> be any compact hypersurface.  Then <img src='http://s0.wp.com/latex.php?latex=M&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='M' title='M' class='latex' /> is contained in the interior of some sphere <img src='http://s0.wp.com/latex.php?latex=S&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='S' title='S' class='latex' />, of radius <img src='http://s0.wp.com/latex.php?latex=R&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='R' title='R' class='latex' />.  Now <img src='http://s0.wp.com/latex.php?latex=S&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='S' title='S' class='latex' /> collapses with radius <img src='http://s0.wp.com/latex.php?latex=r%28t%29%3D%5Csqrt%7BR%5E2-2nt%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='r(t)=&#92;sqrt{R^2-2nt}' title='r(t)=&#92;sqrt{R^2-2nt}' class='latex' />.  By the comparison principle, the flow starting at <img src='http://s0.wp.com/latex.php?latex=M&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='M' title='M' class='latex' /> stays inside the region bounded by <img src='http://s0.wp.com/latex.php?latex=r%28t%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='r(t)' title='r(t)' class='latex' />; in particular <img src='http://s0.wp.com/latex.php?latex=M&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='M' title='M' class='latex' /> develops a singularity before time <img src='http://s0.wp.com/latex.php?latex=t%3D%5Cfrac%7BR%5E2%7D%7B2n%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='t=&#92;frac{R^2}{2n}' title='t=&#92;frac{R^2}{2n}' class='latex' />.  Sometimes, the singularity <img src='http://s0.wp.com/latex.php?latex=%5C%7BM_t%5C%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;{M_t&#92;}' title='&#92;{M_t&#92;}' class='latex' /> achieves is collapse to a point, as in the case of the sphere.  We have</p>
<blockquote><p><strong>Huisken 1984</strong>. Suppose <img src='http://s0.wp.com/latex.php?latex=M&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='M' title='M' class='latex' /> is uniformly convex, i.e. <img src='http://s0.wp.com/latex.php?latex=%5Clambda_i%5Cgeq+%5Calpha%3E0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;lambda_i&#92;geq &#92;alpha&gt;0' title='&#92;lambda_i&#92;geq &#92;alpha&gt;0' class='latex' /> where <img src='http://s0.wp.com/latex.php?latex=%5Clambda_i&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;lambda_i' title='&#92;lambda_i' class='latex' /> are the principal curvatures.  Then <img src='http://s0.wp.com/latex.php?latex=M&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='M' title='M' class='latex' /> is isotopic to a round sphere, with the isotopy given by a rescaled flow.</p></blockquote>
<p>What happens when we relax the convexity assumption?  We say a hypersurface<em> </em>is<em> 2-convex</em> if <img src='http://s0.wp.com/latex.php?latex=%5Clambda_1%2B%5Clambda_2%3E0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;lambda_1+&#92;lambda_2&gt;0' title='&#92;lambda_1+&#92;lambda_2&gt;0' class='latex' />, where <img src='http://s0.wp.com/latex.php?latex=%5Clambda_1%5Cleq%5Clambda_2%5Cleq%5Ccdots%5Cleq%5Clambda_n&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;lambda_1&#92;leq&#92;lambda_2&#92;leq&#92;cdots&#92;leq&#92;lambda_n' title='&#92;lambda_1&#92;leq&#92;lambda_2&#92;leq&#92;cdots&#92;leq&#92;lambda_n' class='latex' /> are the principal curvatures.  This is equivalent to there being at most one negative principal curvature, which is also the smallest.</p>
<blockquote><p><strong>Huisken-Sinestrari 2008</strong>.  Suppose <img src='http://s0.wp.com/latex.php?latex=M&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='M' title='M' class='latex' /> is closed and 2-convex.  Then <img src='http://s0.wp.com/latex.php?latex=M&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='M' title='M' class='latex' /> is diffeomorphic to <img src='http://s0.wp.com/latex.php?latex=%5C%23_k+S%5E%7Bn-1%7D%5Ctimes+S%5E1&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;#_k S^{n-1}&#92;times S^1' title='&#92;#_k S^{n-1}&#92;times S^1' class='latex' />, i.e. the boundary of a handlebody.  Moreover the flow detects the connect sums.</p>
<p><span id="more-74"></span></p></blockquote>
<p>In particular, we&#8217;re going to need to understand what happens with two copies of <img src='http://s0.wp.com/latex.php?latex=S%5E%7Bn-1%7D%5Ctimes+S%5E1&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='S^{n-1}&#92;times S^1' title='S^{n-1}&#92;times S^1' class='latex' /> connected by a long, thin tube.  It&#8217;s clear that if the tube is long and thin enough, it will collapse before either of the <img src='http://s0.wp.com/latex.php?latex=S%5E%7Bn-1%7D%5Ctimes+S%5E1&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='S^{n-1}&#92;times S^1' title='S^{n-1}&#92;times S^1' class='latex' /> summands achieves a singularity.  So we&#8217;ll start by defining our singularity resolution procedure on such long, thin collapsing necks.</p>
<p>For our notion of neck, we&#8217;re going to use Hamilton&#8217;s idea.  A Hamilton neck is an embedding <img src='http://s0.wp.com/latex.php?latex=N%3AS%5E%7Bn-1%7D%5Ctimes%5B-4%5CLambda%2C4%5CLambda%5D%5Crightarrow+M&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='N:S^{n-1}&#92;times[-4&#92;Lambda,4&#92;Lambda]&#92;rightarrow M' title='N:S^{n-1}&#92;times[-4&#92;Lambda,4&#92;Lambda]&#92;rightarrow M' class='latex' />, such that the pullback metric <img src='http://s0.wp.com/latex.php?latex=N%5E%2Ag&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='N^*g' title='N^*g' class='latex' /> is close to the standard round metric. (As with <img src='http://s0.wp.com/latex.php?latex=F&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='F' title='F' class='latex' />, I&#8217;ll blur the distinction between <img src='http://s0.wp.com/latex.php?latex=N&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='N' title='N' class='latex' /> and its image.)  Suppose we have such a neck.</p>
<blockquote><p><strong>Surgery Procedure &#8211; Collapsing Neck Case</strong>.  Given a Hamilton neck, cut a region out of the middle of the neck, pinch the ends in a little, and cap them off, as in the figure.</p></blockquote>
<p style="text-align:center;"><img class="aligncenter" src="http://thecooper.files.wordpress.com/2009/01/cut.jpg?w=300" alt="" width="300" /><br />
That&#8217;s a little nontechnical, but it turns out:</p>
<blockquote><p><strong>Lemma</strong>.  The surgery procedure can be defined so that surgery <em>decreases</em> area, <em>increases</em> H, and <em>increases</em> <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B%5Clambda_1%2B%5Clambda_2%7D%7BH%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;frac{&#92;lambda_1+&#92;lambda_2}{H}' title='&#92;frac{&#92;lambda_1+&#92;lambda_2}{H}' class='latex' />, all by positive amounts that depend only on the scale of the neck.</p></blockquote>
<p>Area decrease is a very coarse sort of simplification.  <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B%5Clambda_1%2B%5Clambda_2%7D%7BH%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;frac{&#92;lambda_1+&#92;lambda_2}{H}' title='&#92;frac{&#92;lambda_1+&#92;lambda_2}{H}' class='latex' /> is a scale-invariant quantity that measures how 2-convex the surface is; we can think of convexity as being the limit case as <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B%5Clambda_1%2B%5Clambda_2%7D%7BH%7D%5Crightarrow+%5Cinfty&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;frac{&#92;lambda_1+&#92;lambda_2}{H}&#92;rightarrow &#92;infty' title='&#92;frac{&#92;lambda_1+&#92;lambda_2}{H}&#92;rightarrow &#92;infty' class='latex' />.  Since we know how convex things behave under the flow (from Huisken&#8217;s theorem), the increase in <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B%5Clambda_1%2B%5Clambda_2%7D%7BH%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;frac{&#92;lambda_1+&#92;lambda_2}{H}' title='&#92;frac{&#92;lambda_1+&#92;lambda_2}{H}' class='latex' /> is also a simplification of sorts.  I want to claim that, in fact, this case is the only one to consider.  That is, the <strong>only</strong> singularities we see in the 2-convex case are collapsing necks.  To do this, I need to be a little more technical.  Here&#8217;s the real statement of the Huisken-Sinestrari theorem.</p>
<blockquote><p><strong>Surgery Theorem</strong>.  Let <img src='http://s0.wp.com/latex.php?latex=M&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='M' title='M' class='latex' /> be 2-convex and closed.  Then there is a mean curvature flow with surgeries starting from <img src='http://s0.wp.com/latex.php?latex=M&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='M' title='M' class='latex' />, such that:</p>
<ol>
<li>All surgeries are neck-cuttings, and all occur at the same scale <img src='http://s0.wp.com/latex.php?latex=r_1%3D%5Cfrac%7Bn-1%7D%7BH_1%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='r_1=&#92;frac{n-1}{H_1}' title='r_1=&#92;frac{n-1}{H_1}' class='latex' />.</li>
<li>All surgeries occur at times when <img src='http://s0.wp.com/latex.php?latex=H_%7Bmax%7D%3DH_3%5Cgeq+100H_1&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='H_{max}=H_3&#92;geq 100H_1' title='H_{max}=H_3&#92;geq 100H_1' class='latex' />.</li>
<li>After doing surgery, all curvatures higher than <img src='http://s0.wp.com/latex.php?latex=H_2%5Cleq+%5Cfrac%7B1%7D%7B10%7DH_3&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='H_2&#92;leq &#92;frac{1}{10}H_3' title='H_2&#92;leq &#92;frac{1}{10}H_3' class='latex' /> lie on components which are topological <img src='http://s0.wp.com/latex.php?latex=S%5En&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='S^n' title='S^n' class='latex' />s and <img src='http://s0.wp.com/latex.php?latex=S%5E%7Bn-1%7D%5Ctimes+S%5E1&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='S^{n-1}&#92;times S^1' title='S^{n-1}&#92;times S^1' class='latex' /> s.</li>
<li>There are a finite number of surgery times, after which we are left with a disjoint collection of <img src='http://s0.wp.com/latex.php?latex=S%5En&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='S^n' title='S^n' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=S%5E%7Bn-1%7D%5Ctimes+S%5E1&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='S^{n-1}&#92;times S^1' title='S^{n-1}&#92;times S^1' class='latex' />.</li>
</ol>
</blockquote>
<p>This, in turn, implies the  topological classification, since the surgery defined above is just undoing a connect sum.  The theme of the proof of the Surgery Theorem is that &#8220;good surgeries suffice&#8221;.  A good surgery is:</p>
<blockquote><p><strong>Definition.</strong> A flow-with-surgeries <img src='http://s0.wp.com/latex.php?latex=%5C%7BM_t%5C%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;{M_t&#92;}' title='&#92;{M_t&#92;}' class='latex' /> is good if:</p>
<ol>
<li>All surgeries are performed at the same scale <img src='http://s0.wp.com/latex.php?latex=r_1%3D%5Cfrac%7Bn-1%7D%7BH_1%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='r_1=&#92;frac{n-1}{H_1}' title='r_1=&#92;frac{n-1}{H_1}' class='latex' />.</li>
<li>Each surgery looks the same.  In particular, one side of the surgery belongs to a component that is topologically <img src='http://s0.wp.com/latex.php?latex=S%5En&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='S^n' title='S^n' class='latex' /> or <img src='http://s0.wp.com/latex.php?latex=S%5E%7Bn-1%7D%5Ctimes+S%5E1&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='S^{n-1}&#92;times S^1' title='S^{n-1}&#92;times S^1' class='latex' />.  The other side has a long flaring collar which starts at radius <img src='http://s0.wp.com/latex.php?latex=r_1&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='r_1' title='r_1' class='latex' /> and flares to radius <img src='http://s0.wp.com/latex.php?latex=2r_1&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='2r_1' title='2r_1' class='latex' />.</li>
<li>Each surgery is essential to disconnect the <img src='http://s0.wp.com/latex.php?latex=S%5En&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='S^n' title='S^n' class='latex' /> or <img src='http://s0.wp.com/latex.php?latex=S%5E%7Bn-1%7D%5Ctimes+S%5E1&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='S^{n-1}&#92;times S^1' title='S^{n-1}&#92;times S^1' class='latex' /> mentioned above, which also has a point where <img src='http://s0.wp.com/latex.php?latex=H%3E10H_1&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='H&gt;10H_1' title='H&gt;10H_1' class='latex' />.</li>
</ol>
<p style="text-align:center;"><img class="aligncenter" src="http://thecooper.files.wordpress.com/2009/01/good.jpg?w=300" alt="" width="300" /></p>
</blockquote>
<p>The first thing to notice about good surgeries is that they can&#8217;t accumulate spatially; the long collars buffer the surgery regions away from each other spatially.  Each surgery removes the  same amount of area, and area is decreasing along the flow, so we see that there can only be finitely many surgery times.  Thus a good flow-with-surgeries has finitely many surgeries.  So we can induct on the time <img src='http://s0.wp.com/latex.php?latex=t&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='t' title='t' class='latex' />.  In fact this is what we do:</p>
<blockquote><p><strong>Inductive Claim</strong>.  Suppose <img src='http://s0.wp.com/latex.php?latex=%5C%7BM_t%5C%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;{M_t&#92;}' title='&#92;{M_t&#92;}' class='latex' /> is good up to time <img src='http://s0.wp.com/latex.php?latex=t_0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='t_0' title='t_0' class='latex' /> and there is <img src='http://s0.wp.com/latex.php?latex=p_o%5Cin+M_%7Bt_0%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='p_o&#92;in M_{t_0}' title='p_o&#92;in M_{t_0}' class='latex' /> where <img src='http://s0.wp.com/latex.php?latex=H%28p_0%2Ct_0%29%3E10H_1&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='H(p_0,t_0)&gt;10H_1' title='H(p_0,t_0)&gt;10H_1' class='latex' />.  Then we can perform a good surgery to disconnect <img src='http://s0.wp.com/latex.php?latex=%28p_0%2Ct_0%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='(p_0,t_0)' title='(p_0,t_0)' class='latex' /> from the rest of the manifold.</p></blockquote>
<p>This establishes the Surgery Theorem.  So far we haven&#8217;t done any singularity analysis.  In fact I&#8217;m going to relegate it <a href="http://thecooper.wordpress.com/2009/02/01/huisken-and-sinestrari-ii/">to another post</a>.  But the relevant result is:</p>
<blockquote><p><strong>Neck Continuation Theorem.</strong> There exist <img src='http://s0.wp.com/latex.php?latex=H_1%2C%5Ceta_1&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='H_1,&#92;eta_1' title='H_1,&#92;eta_1' class='latex' /> with the following property.  Suppose <img src='http://s0.wp.com/latex.php?latex=%28p_0%2Ct_0%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='(p_0,t_0)' title='(p_0,t_0)' class='latex' /> has <img src='http://s0.wp.com/latex.php?latex=H%28p_0%2Ct_0%29%5Cgeq+10+H_1&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='H(p_0,t_0)&#92;geq 10 H_1' title='H(p_0,t_0)&#92;geq 10 H_1' class='latex' /> and $\frac{\lambda_1}{H}(p_0,t_0)\leq \eta_1$.  Then <img src='http://s0.wp.com/latex.php?latex=%28p_0%2Ct_0%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='(p_0,t_0)' title='(p_0,t_0)' class='latex' /> is the centre of a neck, which can be extended in each direction until either</p>
<ol>
<li>The neck closes up into a cap.</li>
<li>We reach a cross-section of radius <img src='http://s0.wp.com/latex.php?latex=2%5Cfrac%7Bn-1%7D%7BH_1%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='2&#92;frac{n-1}{H_1}' title='2&#92;frac{n-1}{H_1}' class='latex' /></li>
</ol>
<p style="text-align:center;"><img class="aligncenter" src="http://thecooper.files.wordpress.com/2009/01/nct.jpg?w=300" alt="" width="300" /></p>
</blockquote>
<p>So if the point of high curvature we want to remove has <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B%5Clambda_1%7D%7BH%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;frac{&#92;lambda_1}{H}' title='&#92;frac{&#92;lambda_1}{H}' class='latex' /> small, we can find a cross-section with radius <img src='http://s0.wp.com/latex.php?latex=r_1&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='r_1' title='r_1' class='latex' /> (radius is a continuous function which increases from about <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B1%7D%7B10%7Dr_1&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;frac{1}{10}r_1' title='&#92;frac{1}{10}r_1' class='latex' /> at <img src='http://s0.wp.com/latex.php?latex=p_0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='p_0' title='p_0' class='latex' /> to <img src='http://s0.wp.com/latex.php?latex=2r_1&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='2r_1' title='2r_1' class='latex' />); cut there.  In fact we may find either one or two such cross-sections.  In any case, the long collar exists, and the other side of the surgery is topologically recognised, so this surgery is good.</p>
<p>The other case, when <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B%5Clambda_1%7D%7BH%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;frac{&#92;lambda_1}{H}' title='&#92;frac{&#92;lambda_1}{H}' class='latex' /> is large, we make an end-run around, and find a nearby point where <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B%5Clambda_1%7D%7BH%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;frac{&#92;lambda_1}{H}' title='&#92;frac{&#92;lambda_1}{H}' class='latex' /> is small.  This relies on what I call the Huisken Alternative.</p>
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		<title>proving sup bounds using Lp bounds and iteration</title>
		<link>http://thecooper.wordpress.com/2008/09/04/proving-sup-bounds-using-lp-bounds-and-iteration/</link>
		<comments>http://thecooper.wordpress.com/2008/09/04/proving-sup-bounds-using-lp-bounds-and-iteration/#comments</comments>
		<pubDate>Thu, 04 Sep 2008 21:39:36 +0000</pubDate>
		<dc:creator>thecooper</dc:creator>
				<category><![CDATA[math posts]]></category>
		<category><![CDATA[prerequisites required]]></category>
		<category><![CDATA[problems of existence]]></category>
		<category><![CDATA[severe]]></category>
		<category><![CDATA[estimates]]></category>
		<category><![CDATA[huisken]]></category>
		<category><![CDATA[mean curvature flow]]></category>

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		<description><![CDATA[Sorry for the break.  Got a lot on my plate. A trick that&#8217;s come up a lot in my recent readings is using an bound to get a bound on the supremum of some function.  The trivial case is what happens when where the constant is independent of ; then we just use the fact [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=thecooper.wordpress.com&amp;blog=3799271&amp;post=59&amp;subd=thecooper&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>Sorry for the break.  Got a lot on my plate.</p>
<p>A trick that&#8217;s come up a lot in my recent readings is using an <img src='http://s0.wp.com/latex.php?latex=L%5Ep&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='L^p' title='L^p' class='latex' /> bound to get a bound on the supremum of some function.  The trivial case is what happens when <img src='http://s0.wp.com/latex.php?latex=%5Cint+f%5Ep+%5Cleq+C&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;int f^p &#92;leq C' title='&#92;int f^p &#92;leq C' class='latex' /> where the constant <img src='http://s0.wp.com/latex.php?latex=C&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='C' title='C' class='latex' /> is independent of <img src='http://s0.wp.com/latex.php?latex=p&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='p' title='p' class='latex' />; then we just use the fact that the sup norm is the limit of the <img src='http://s0.wp.com/latex.php?latex=L%5Ep&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='L^p' title='L^p' class='latex' /> norms.  But what if the constant <img src='http://s0.wp.com/latex.php?latex=C&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='C' title='C' class='latex' /> depends on <img src='http://s0.wp.com/latex.php?latex=p&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='p' title='p' class='latex' />, and in fact blows up as <img src='http://s0.wp.com/latex.php?latex=p&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='p' title='p' class='latex' /> blows up?  Turns out all is not lost.</p>
<p>I&#8217;ll use the main theorem from Huisken 1984 as an example, though the same trick is used in Hamilton 1982 and Huisken-Sinestrari 1999.   The theorem is</p>
<p style="text-align:left;padding-left:30px;"><strong>Theorem.</strong> Suppose <img src='http://s0.wp.com/latex.php?latex=M&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='M' title='M' class='latex' /> is a closed convex hypersurface.  Then there exist constants <img src='http://s0.wp.com/latex.php?latex=C_0%3C%5Cinfty%2C%5Cdelta%3E0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='C_0&lt;&#92;infty,&#92;delta&gt;0' title='C_0&lt;&#92;infty,&#92;delta&gt;0' class='latex' /> such that <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B%7CA%7C%5E2%7D%7BH%5E2%7D-%5Cfrac%7B1%7D%7Bn%7D%5Cleq+CH%5E%7B-%5Cdelta%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;frac{|A|^2}{H^2}-&#92;frac{1}{n}&#92;leq CH^{-&#92;delta}' title='&#92;frac{|A|^2}{H^2}-&#92;frac{1}{n}&#92;leq CH^{-&#92;delta}' class='latex' /> along a mean curvature flow starting from <img src='http://s0.wp.com/latex.php?latex=M&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='M' title='M' class='latex' />.</p>
<p>The way to prove this is to consider the function <img src='http://s0.wp.com/latex.php?latex=f%3Df_%5Cdelta%3DH%5E%7B%5Cdelta-2%7D%28%7CA%7C%5E2-%5Cfrac%7B1%7D%7Bn%7DH%5E2%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='f=f_&#92;delta=H^{&#92;delta-2}(|A|^2-&#92;frac{1}{n}H^2)' title='f=f_&#92;delta=H^{&#92;delta-2}(|A|^2-&#92;frac{1}{n}H^2)' class='latex' /> and try to prove that for some choice of <img src='http://s0.wp.com/latex.php?latex=%5Cdelta&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;delta' title='&#92;delta' class='latex' />, it&#8217;s bounded.  Clearly the function is bounded at each time, but we need to keep the bounds from blowing up as we approach the first singular time.</p>
<p>There is an important fact we&#8217;re going to use about the function <img src='http://s0.wp.com/latex.php?latex=f&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='f' title='f' class='latex' />.  It can absorb powers of <img src='http://s0.wp.com/latex.php?latex=H&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='H' title='H' class='latex' />; that is, for any integer <img src='http://s0.wp.com/latex.php?latex=m&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='m' title='m' class='latex' />, we have <img src='http://s0.wp.com/latex.php?latex=H%5Emf_%5Cdelta%5Ep%3Df_%5Cgamma%5E%7Bp%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='H^mf_&#92;delta^p=f_&#92;gamma^{p}' title='H^mf_&#92;delta^p=f_&#92;gamma^{p}' class='latex' /> for <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%3DO%28p%5E%7B-%5Cfrac%7B1%7D%7B2%7D%7D%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;gamma=O(p^{-&#92;frac{1}{2}})' title='&#92;gamma=O(p^{-&#92;frac{1}{2}})' class='latex' />.  Thus if we prove a <img src='http://s0.wp.com/latex.php?latex=L%5Ep&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='L^p' title='L^p' class='latex' /> bound for <img src='http://s0.wp.com/latex.php?latex=f&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='f' title='f' class='latex' />, we get <img src='http://s0.wp.com/latex.php?latex=L%5Ep&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='L^p' title='L^p' class='latex' /> bounds for <img src='http://s0.wp.com/latex.php?latex=H%5E%7B%5Cfrac%7Bm%7D%7Bp%7D%7Df&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='H^{&#92;frac{m}{p}}f' title='H^{&#92;frac{m}{p}}f' class='latex' /> as well.</p>
<p>Now with a lot of tinkering (which is the hard part of the paper, and is different for different geometric assumptions), you can show that</p>
<p style="text-align:left;padding-left:30px;"><strong>Lemma</strong>.  There is a constant <img src='http://s0.wp.com/latex.php?latex=D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='D' title='D' class='latex' /> so that if <img src='http://s0.wp.com/latex.php?latex=p&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='p' title='p' class='latex' /> is large and <img src='http://s0.wp.com/latex.php?latex=%5Cdelta%3DO%28p%5E%7B-%5Cfrac%7B1%7D%7B2%7D%7D%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;delta=O(p^{-&#92;frac{1}{2}})' title='&#92;delta=O(p^{-&#92;frac{1}{2}})' class='latex' />, we have <img src='http://s0.wp.com/latex.php?latex=%5Cint+f_%5Cdelta%5Ep%5Cleq+D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;int f_&#92;delta^p&#92;leq D' title='&#92;int f_&#92;delta^p&#92;leq D' class='latex' />.</p>
<p style="text-align:left;">Now we want to consider the function <img src='http://s0.wp.com/latex.php?latex=v%3Dv_k%3D%28f-k%29_%2B%5E%5Cfrac%7Bp%7D%7B2%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='v=v_k=(f-k)_+^&#92;frac{p}{2}' title='v=v_k=(f-k)_+^&#92;frac{p}{2}' class='latex' />.  Notice that <img src='http://s0.wp.com/latex.php?latex=v_k%5E2&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='v_k^2' title='v_k^2' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=f%5Ep&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='f^p' title='f^p' class='latex' /> differ only by a constant.  Using the evolution equation for <img src='http://s0.wp.com/latex.php?latex=f&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='f' title='f' class='latex' />, we can show without much fuss that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bd%7D%7Bdt%7D%5Cint+v_k%5E2%2B%5Cint+%7C%5Cnabla+v_k%7C%5E2%5Cleq+%5Cdelta+p%5Cint+H%5E2f%5Ep&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;frac{d}{dt}&#92;int v_k^2+&#92;int |&#92;nabla v_k|^2&#92;leq &#92;delta p&#92;int H^2f^p' title='&#92;frac{d}{dt}&#92;int v_k^2+&#92;int |&#92;nabla v_k|^2&#92;leq &#92;delta p&#92;int H^2f^p' class='latex' /></p>
<p style="text-align:left;">Now we use the Michael-Simon Sobolev inequality <img src='http://s0.wp.com/latex.php?latex=%28%5Cint+g%5E%5Cfrac%7Bn%7D%7Bn-1%7D%29%5E%7B%5Cfrac%7Bn-1%7D%7Bn%7D%7D%5Cleq+C%28n%29%28%5Cint+%7C%5Cnabla+g%7C%2B%5Cint+Hg%29&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='(&#92;int g^&#92;frac{n}{n-1})^{&#92;frac{n-1}{n}}&#92;leq C(n)(&#92;int |&#92;nabla g|+&#92;int Hg)' title='(&#92;int g^&#92;frac{n}{n-1})^{&#92;frac{n-1}{n}}&#92;leq C(n)(&#92;int |&#92;nabla g|+&#92;int Hg)' class='latex' /> with <img src='http://s0.wp.com/latex.php?latex=g%3Dv_k%5E%7B%5Cfrac%7B2%28n-1%29%7D%7Bn-2%7D%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='g=v_k^{&#92;frac{2(n-1)}{n-2}}' title='g=v_k^{&#92;frac{2(n-1)}{n-2}}' class='latex' /> and the Holder inequality to get</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%28%5Cint+v_k%5E%5Cfrac%7B2n%7D%7Bn-2%7D%29%5E%5Cfrac%7Bn-2%7D%7Bn%7D%5Cleq+C%28%5Cint%7C%5Cnabla+v_k%7C%5E2%2B%28%5Cint+H%5En%29%5E%5Cfrac%7B2%7D%7Bn%7D%28%5Cint+v_k%5E%5Cfrac%7B2n%7D%7Bn-2%7D%29%5E%5Cfrac%7Bn-2%7D%7Bn%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='(&#92;int v_k^&#92;frac{2n}{n-2})^&#92;frac{n-2}{n}&#92;leq C(&#92;int|&#92;nabla v_k|^2+(&#92;int H^n)^&#92;frac{2}{n}(&#92;int v_k^&#92;frac{2n}{n-2})^&#92;frac{n-2}{n}' title='(&#92;int v_k^&#92;frac{2n}{n-2})^&#92;frac{n-2}{n}&#92;leq C(&#92;int|&#92;nabla v_k|^2+(&#92;int H^n)^&#92;frac{2}{n}(&#92;int v_k^&#92;frac{2n}{n-2})^&#92;frac{n-2}{n}' class='latex' /></p>
<p style="text-align:left;">where all integrals are taken over the support of <img src='http://s0.wp.com/latex.php?latex=v_k&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='v_k' title='v_k' class='latex' />, i.e. the region where <img src='http://s0.wp.com/latex.php?latex=f%5Cgeq+k&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='f&#92;geq k' title='f&#92;geq k' class='latex' />.  Notice that the left-hand side occurs on the right as well.</p>
<p style="text-align:left;">Now <img src='http://s0.wp.com/latex.php?latex=H%5En+%5Cleq+H%5En+f%5Ep+k%5E%7B-p%7D+&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='H^n &#92;leq H^n f^p k^{-p} ' title='H^n &#92;leq H^n f^p k^{-p} ' class='latex' /> on the support of <img src='http://s0.wp.com/latex.php?latex=v_k&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='v_k' title='v_k' class='latex' />, so we have <img src='http://s0.wp.com/latex.php?latex=%5Cint+H%5En%5Cleq+k%5E%7B-p%7DD&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;int H^n&#92;leq k^{-p}D' title='&#92;int H^n&#92;leq k^{-p}D' class='latex' />, where <img src='http://s0.wp.com/latex.php?latex=D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='D' title='D' class='latex' /> is the sup bound.  So we have</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bd%7D%7Bdt%7D%5Cint+v_k%5E2%2BD%27%28%5Cint+v_k%5E%5Cfrac%7B2n%7D%7Bn-2%7D%29%5E%5Cfrac%7Bn-2%7D%7Bn%7D%5Cleq+%5Cdelta+p%5Cint+H%5E2+f%5Ep&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;frac{d}{dt}&#92;int v_k^2+D&#039;(&#92;int v_k^&#92;frac{2n}{n-2})^&#92;frac{n-2}{n}&#92;leq &#92;delta p&#92;int H^2 f^p' title='&#92;frac{d}{dt}&#92;int v_k^2+D&#039;(&#92;int v_k^&#92;frac{2n}{n-2})^&#92;frac{n-2}{n}&#92;leq &#92;delta p&#92;int H^2 f^p' class='latex' /></p>
<p style="text-align:left;">Now integrate both sides in <img src='http://s0.wp.com/latex.php?latex=t&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='t' title='t' class='latex' /> to get</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cint_%7BM_T%7D+v_k%5E2-%5Cint_%7BM_0%7Dv_k%5E2%2BD%27%5Cint_0%5ET%28%5Cint+v_k%5E%5Cfrac%7B2n%7D%7Bn-2%7D%29%5E%5Cfrac%7Bn-2%7D%7Bn%7D%5Cleq+%5Cdelta+p%5Cint_0%5ET%5Cint+H%5E2+f%5Ep&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;int_{M_T} v_k^2-&#92;int_{M_0}v_k^2+D&#039;&#92;int_0^T(&#92;int v_k^&#92;frac{2n}{n-2})^&#92;frac{n-2}{n}&#92;leq &#92;delta p&#92;int_0^T&#92;int H^2 f^p' title='&#92;int_{M_T} v_k^2-&#92;int_{M_0}v_k^2+D&#039;&#92;int_0^T(&#92;int v_k^&#92;frac{2n}{n-2})^&#92;frac{n-2}{n}&#92;leq &#92;delta p&#92;int_0^T&#92;int H^2 f^p' class='latex' /></p>
<p style="text-align:left;">and choose <img src='http://s0.wp.com/latex.php?latex=k&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='k' title='k' class='latex' /> so large that <img src='http://s0.wp.com/latex.php?latex=f%5Cgeq+k&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='f&#92;geq k' title='f&#92;geq k' class='latex' /> everywhere on <img src='http://s0.wp.com/latex.php?latex=M_0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='M_0' title='M_0' class='latex' />.  In particular,</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=D%27%5Cint_0%5ET%28%5Cint+v_k%5E%5Cfrac%7B2n%7D%7Bn-2%7D%29%5E%5Cfrac%7Bn-2%7D%7Bn%7D%5Cleq+%5Cdelta+p%5Cint_0%5ET%5Cint+H%5E2+f%5Ep&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='D&#039;&#92;int_0^T(&#92;int v_k^&#92;frac{2n}{n-2})^&#92;frac{n-2}{n}&#92;leq &#92;delta p&#92;int_0^T&#92;int H^2 f^p' title='D&#039;&#92;int_0^T(&#92;int v_k^&#92;frac{2n}{n-2})^&#92;frac{n-2}{n}&#92;leq &#92;delta p&#92;int_0^T&#92;int H^2 f^p' class='latex' /></p>
<p style="text-align:left;">So we can estimate integrals of <img src='http://s0.wp.com/latex.php?latex=v_k&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='v_k' title='v_k' class='latex' /> by integrals of <img src='http://s0.wp.com/latex.php?latex=H%5E2f%5Ep&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='H^2f^p' title='H^2f^p' class='latex' />.  Some more Holder and interpolation inequalities give</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%28%5Cint+v_k%5E%7B2q%7D%29%5E%5Cfrac%7B1%7D%7Bq%7D%5Cleq+D%27%5Cdelta+p%5Cint%5Cint+H%5E2+f%5Ep&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='(&#92;int v_k^{2q})^&#92;frac{1}{q}&#92;leq D&#039;&#92;delta p&#92;int&#92;int H^2 f^p' title='(&#92;int v_k^{2q})^&#92;frac{1}{q}&#92;leq D&#039;&#92;delta p&#92;int&#92;int H^2 f^p' class='latex' /></p>
<p style="text-align:left;">and using Holder again (stupidly this time&#8211;just pull a power of the volume out), this becomes</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%5Cint+v_k%5E2%5Cleq+D%27%5Cdelta+p+%7C%7CA%28k%29%7C%7C%5E%7B2-%5Cfrac%7B1%7D%7Bq%7D-%5Cfrac%7B1%7D%7Br%7D%7D%28%5Cint%5Cint+H%5E%7B2r%7D+f%5E%7Bpr%7D%29%5E%5Cfrac%7B1%7D%7Br%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;int v_k^2&#92;leq D&#039;&#92;delta p ||A(k)||^{2-&#92;frac{1}{q}-&#92;frac{1}{r}}(&#92;int&#92;int H^{2r} f^{pr})^&#92;frac{1}{r}' title='&#92;int v_k^2&#92;leq D&#039;&#92;delta p ||A(k)||^{2-&#92;frac{1}{q}-&#92;frac{1}{r}}(&#92;int&#92;int H^{2r} f^{pr})^&#92;frac{1}{r}' class='latex' /></p>
<p style="text-align:left;">where <img src='http://s0.wp.com/latex.php?latex=%7C%7CA%28k%29%7C%7C&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='||A(k)||' title='||A(k)||' class='latex' /> is the space-time volume of the support of <img src='http://s0.wp.com/latex.php?latex=v_k&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='v_k' title='v_k' class='latex' />.  Now if <img src='http://s0.wp.com/latex.php?latex=h%3Ek&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='h&gt;k' title='h&gt;k' class='latex' />, we have <img src='http://s0.wp.com/latex.php?latex=%7Ch-k%7C%5Ep%5Cleq+v_k%5E2&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='|h-k|^p&#92;leq v_k^2' title='|h-k|^p&#92;leq v_k^2' class='latex' />, so we get that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%7Ch-k%7C%5Ep%7C%7CA%28h%29%7C%7C%5Cleq+DD%27%5Cdelta+p+%7C%7CA%28k%29%7C%7C%5E%7B2-%5Cfrac%7B1%7D%7Bq%7D-%5Cfrac%7B1%7D%7Br%7D%7D&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='|h-k|^p||A(h)||&#92;leq DD&#039;&#92;delta p ||A(k)||^{2-&#92;frac{1}{q}-&#92;frac{1}{r}}' title='|h-k|^p||A(h)||&#92;leq DD&#039;&#92;delta p ||A(k)||^{2-&#92;frac{1}{q}-&#92;frac{1}{r}}' class='latex' /></p>
<p style="text-align:left;">which is a sort of decay estimate on the function <img src='http://s0.wp.com/latex.php?latex=k+%5Cmapsto+%7C%7CA%28k%29%7C%7C&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='k &#92;mapsto ||A(k)||' title='k &#92;mapsto ||A(k)||' class='latex' />.  If we choose <img src='http://s0.wp.com/latex.php?latex=r&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='r' title='r' class='latex' /> big enough that the exponent on the RHS is greater than 1, this estimate says that if <img src='http://s0.wp.com/latex.php?latex=%7C%7CA%28k%29%7C%7C&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='||A(k)||' title='||A(k)||' class='latex' /> is small, <img src='http://s0.wp.com/latex.php?latex=%7C%7CA%28h%29%7C%7C&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='||A(h)||' title='||A(h)||' class='latex' /> has to be much smaller.  So the volume <img src='http://s0.wp.com/latex.php?latex=%7C%7CA%28k%29%7C%7C&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='||A(k)||' title='||A(k)||' class='latex' /> is decaying pretty fast. More specifically,</p>
<p style="text-align:left;padding-left:30px;"><strong>Stampacchia&#8217;s Lemma.</strong> Suppose <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' /> is a nonincreasing real function, which satisfies for all <img src='http://s0.wp.com/latex.php?latex=h%3Ek&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='h&gt;k' title='h&gt;k' class='latex' />,</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=%7Ch-k%7C%5E%5Calpha+%5Cphi%28h%29%5Cleq+C%5Cphi%28k%29%5E%5Cgamma&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='|h-k|^&#92;alpha &#92;phi(h)&#92;leq C&#92;phi(k)^&#92;gamma' title='|h-k|^&#92;alpha &#92;phi(h)&#92;leq C&#92;phi(k)^&#92;gamma' class='latex' /></p>
<p style="text-align:left;padding-left:30px;">where <img src='http://s0.wp.com/latex.php?latex=C%2C%5Calpha%3E0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='C,&#92;alpha&gt;0' title='C,&#92;alpha&gt;0' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Cgamma%3E1&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;gamma&gt;1' title='&#92;gamma&gt;1' class='latex' />.  Then there is a number <img src='http://s0.wp.com/latex.php?latex=d%3C%5Cinfty&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='d&lt;&#92;infty' title='d&lt;&#92;infty' class='latex' /> with <img src='http://s0.wp.com/latex.php?latex=%5Cphi%28d%29%3D0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='&#92;phi(d)=0' title='&#92;phi(d)=0' class='latex' />.</p>
<p style="text-align:left;">Thus we get a number <img src='http://s0.wp.com/latex.php?latex=k_0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='k_0' title='k_0' class='latex' /> for which <img src='http://s0.wp.com/latex.php?latex=%7C%7CA%28k_0%29%7C%7C%3D0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='||A(k_0)||=0' title='||A(k_0)||=0' class='latex' />, that is, for which <img src='http://s0.wp.com/latex.php?latex=f%5Cleq+k_0&amp;bg=fff&amp;fg=1c1c1c&amp;s=0' alt='f&#92;leq k_0' title='f&#92;leq k_0' class='latex' /> on the entire flow.</p>
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		<title>for Megan especially</title>
		<link>http://thecooper.wordpress.com/2008/07/17/for-megan-especially/</link>
		<comments>http://thecooper.wordpress.com/2008/07/17/for-megan-especially/#comments</comments>
		<pubDate>Thu, 17 Jul 2008 15:58:50 +0000</pubDate>
		<dc:creator>thecooper</dc:creator>
				<category><![CDATA[mathematisation]]></category>
		<category><![CDATA[nonmath posts]]></category>
		<category><![CDATA[science]]></category>

		<guid isPermaLink="false">http://thecooper.wordpress.com/?p=51</guid>
		<description><![CDATA[This article talks about the sort of math one can use to compare fossils (or living creatures), and the benefits that making said comparisons rigorous can have. via Ars Mathematica<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=thecooper.wordpress.com&amp;blog=3799271&amp;post=51&amp;subd=thecooper&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><a href="http://www.claymath.org/library/05report_featurearticle.pdf">This article</a> talks about the sort of math one can use to compare fossils (or living creatures), and the benefits that making said comparisons rigorous can have.</p>
<p>via <a href="http://www.arsmathematica.net/">Ars Mathematica</a></p>
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		<title>fuzzy sets and God</title>
		<link>http://thecooper.wordpress.com/2008/07/17/fuzzy-sets-and-god/</link>
		<comments>http://thecooper.wordpress.com/2008/07/17/fuzzy-sets-and-god/#comments</comments>
		<pubDate>Thu, 17 Jul 2008 15:42:26 +0000</pubDate>
		<dc:creator>thecooper</dc:creator>
				<category><![CDATA[nonmath posts]]></category>
		<category><![CDATA[problems of existence]]></category>
		<category><![CDATA[public ignorance of mathematics]]></category>
		<category><![CDATA[fuzzy]]></category>
		<category><![CDATA[logic]]></category>
		<category><![CDATA[topos theory]]></category>

		<guid isPermaLink="false">http://thecooper.wordpress.com/?p=46</guid>
		<description><![CDATA[It&#8217;s been a while. Teaching does that. But back to the game. Many times presuppositionalist apologists will bring up the nice crispness of logic and its unexplained utility for understanding the world as proof that God exists. There&#8217;s rationality out there, they say, which means there must be some intelligence, much like the rationality in [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=thecooper.wordpress.com&amp;blog=3799271&amp;post=46&amp;subd=thecooper&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><strong>It&#8217;s been a while.  Teaching does that.</strong> But back to the game.</p>
<p>Many times presuppositionalist apologists will bring up the nice crispness of logic and its unexplained utility for understanding the world as proof that God exists.  There&#8217;s rationality out there, they say, which means there must be some intelligence, much like the rationality in our own heads is a product of intelligence.</p>
<p>I don&#8217;t find this convincing in the least, but I bring it up because today I came across <a href="http://godofcreation.com/essays/display.asp?ind=69">an argument for the existence of God</a> which takes the opposite tack, namely an appeal to fuzzy logic.</p>
<p><span id="more-46"></span></p>
<p>Fuzzy math is what you get if, instead of expecting a yes-or-no (1 or 0) answer to the question &#8216;Does element x belong to set X?&#8217;, you expect a number between 0 and 1.  So you could answer that x .3-belongs to X.</p>
<p>There are a couple of interpretations available:</p>
<ul>
<li>the number represents a probability.  That is, there is a 30% chance that x actually belongs to X.  This makes fuzzy sets pretty useful in the presence of uncertainty, ala quantum mechanics, or statistics, or anything like that.</li>
<li>the number represents well, fuzziness.  This is useful in modeling, say, the salt concentration of an estuary.</li>
</ul>
<p>The point that the author, Fritz Ward, wants to make is that it&#8217;s perfectly possible, in fuzzy set theory, to have a set X and an element x such that x is neither in X nor in the complement of X.  Translated into logic, this says that a statement can be neither true nor false, but fall somewhere in between.</p>
<p>Ward wants to use this to just avoid the whole theodicy mess:</p>
<blockquote><p>It is pleasing, in a way, that atheists can no longer rely on science to defend their position, and they are left with putting together trite syllogisms like: If God is all powerful and all knowing and all good, then evil cannot exist. But evil does exist, therefore God cannot. Implicit in this argument is the idea that the attributes some theologians (and many Christians) ascribe to God contradict, and this &#8220;proves&#8221; God does not exist. And frankly, its a pretty silly argument.</p></blockquote>
<p>Perhaps the most fundamental misunderstanding comes by way of introducing the reader to the basic thrust of his argument:</p>
<blockquote><p>This letter is my first attempt to fully come to grips with what the implications of fuzzy logic are, and why they offer such profound insights to people of faith. They also, incidentally, destroy traditional logic, and with it, the last remaining refuge of atheism.</p></blockquote>
<p>There are two things wrong here.</p>
<p><strong>One</strong>, it&#8217;s simply not true that fuzzy set theory (or any of the rest of topos theory) does anything like &#8216;destroy traditional logic&#8217;.  Traditional logic works just fine, and is applicable to pretty much every situation it was applicable to before; it&#8217;s just that now we have a framework for dealing with new situations.</p>
<p>When people pulled their heads out of their asses about the Fifth Postulate, and realised that hyperbolic geometries worked just fine, even better, for a lot of applications, that didn&#8217;t mean all of a sudden plane (bah-dum-sh!) euclidean geometry stopped being true.</p>
<p><strong>Two</strong>, there&#8217;s a majorly self-defeating flaw in Ward&#8217;s argument.  He wants to argue as follows:</p>
<ol>
<li>Subscribing to traditional logic is the only way to be an atheist.</li>
<li>Traditional logic has been exploded.</li>
<li>Therefore it is untenable to be an atheist.</li>
</ol>
<p>The problem is that this argument is of the very same modus tollens form as the problem-of-evil formulation he&#8217;s arguing against.  He certainly doesn&#8217;t offer any way to distinguish the two situations.  He could easily, if he understands fuzzy logic so well, come up with a fuzzy-logic formulation of his argument, and prove that the problem-of-evil doesn&#8217;t have any such formulation.</p>
<p>But he neglects to do so, which I think is just indicative that he&#8217;s used to thinking non-fuzzily (crisply?).</p>
<p>What&#8217;s going on here?  Another quote:</p>
<blockquote><p>For the last century or so, beginning with Bertrand Russell, the foundations for traditional logic: in particular the bivalent claim that one cannot have both A and Not A simultaneously has crumbled. It now appears, in fact, that not only can one have both A and Not A, but that the law of the excluded middle doesn&#8217;t apply anywhere in the real world, and does not, in fact, even apply in mathematics.</p></blockquote>
<p>Aha! Here Ward conflates the</p>
<p style="padding-left:30px;"><strong>Principle of Contradiction</strong>.  Can&#8217;t have A and not-A.</p>
<p>with the</p>
<p style="padding-left:30px;"><strong>Law of the Excluded Middle</strong>.  Either A or not-A .</p>
<p>There&#8217;s a huge difference here.  The PC says that A and not-A are disjoint; LEM says that A and not-A cover all the possibilities.  Fuzzy logic, while it allows you to say things like &#8220;.5 A&#8221;, does not allow for &#8220;A and not-A&#8221; or even &#8220;.3 A and .5 not-A&#8221;.</p>
<p>We also have the issue of the fact that there&#8217;s more than one fuzzy logic.  Why restrict oneself to truth values between 0 and 1?  Why not take truth values that are any real number?  Or truth values parametrised by a projective variety?  In fact people do research those logics, in a field of math called <em>topos theory</em>.</p>
<p>What&#8217;s interesting, and instructive for Dr. Ward, is that these researches are carried out <em>within the framework of traditional logic</em>.   To prove a fuzzy logic theorem, you use ordinary logic, by constructing an ordinary-logic model of fuzzy logic.  It&#8217;s again analogous to the different geometries; the Poincaré disc is a hyperbolic plane which can be embedded in the euclidean plane, so that one can use euclidean techniques to prove hyperbolic facts.</p>
<p>This may seem a little inelegant (it would be more satisfying to use all-hyperbolic or all-fuzzy techniques), but it works.</p>
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		<title>Huisken and Sinestrari 1999, pt. 4</title>
		<link>http://thecooper.wordpress.com/2008/06/28/huisken-and-sinestrari-1999-pt-4/</link>
		<comments>http://thecooper.wordpress.com/2008/06/28/huisken-and-sinestrari-1999-pt-4/#comments</comments>
		<pubDate>Sat, 28 Jun 2008 04:54:20 +0000</pubDate>
		<dc:creator>thecooper</dc:creator>
				<category><![CDATA[math posts]]></category>
		<category><![CDATA[mean curvature flow]]></category>
		<category><![CDATA[moderate]]></category>
		<category><![CDATA[prerequisites required]]></category>
		<category><![CDATA[elementary symmetric polynomials]]></category>
		<category><![CDATA[huisken]]></category>
		<category><![CDATA[sinestrari]]></category>

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		<description><![CDATA[So I think I figured out basically what&#8217;s going on with those cones . We needed them to be convex, so we could apply Hamilton&#8217;s maximum principle for systems. Recall that the elementary symmetric polynomials on are defined by If we let denote the polynomial formed by omitting from without the terms involving . It&#8217;s [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=thecooper.wordpress.com&amp;blog=3799271&amp;post=41&amp;subd=thecooper&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>So I think I figured out basically what&#8217;s going on with <a href="http://thecooper.wordpress.com/2008/06/04/huisken-and-sinestrari-1999-pt-2/">those cones</a> <img src='http://s0.wp.com/latex.php?latex=%5CGamma_k&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;Gamma_k' title='&#92;Gamma_k' class='latex' />.  We needed them to be convex, so we could apply Hamilton&#8217;s maximum principle for systems.</p>
<p>Recall that the elementary symmetric polynomials on <img src='http://s0.wp.com/latex.php?latex=%5Cmathbb%7BR%7D%5En&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;mathbb{R}^n' title='&#92;mathbb{R}^n' class='latex' /> are defined by</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=S_k%28%5Clambda%29%3D%5Csum_%7Bi_1%3C%5Ccdots%3Ci_k%7D%5Clambda_%7Bi_1%7D%5Ccdots%5Clambda_%7Bi_k%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='S_k(&#92;lambda)=&#92;sum_{i_1&lt;&#92;cdots&lt;i_k}&#92;lambda_{i_1}&#92;cdots&#92;lambda_{i_k}' title='S_k(&#92;lambda)=&#92;sum_{i_1&lt;&#92;cdots&lt;i_k}&#92;lambda_{i_1}&#92;cdots&#92;lambda_{i_k}' class='latex' /></p>
<p style="text-align:left;">If we let <img src='http://s0.wp.com/latex.php?latex=S_%7Bk%2Ci%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='S_{k,i}' title='S_{k,i}' class='latex' /> denote the polynomial formed by omitting from <img src='http://s0.wp.com/latex.php?latex=S_k&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='S_k' title='S_k' class='latex' /> without the terms involving <img src='http://s0.wp.com/latex.php?latex=%5Clambda_i&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;lambda_i' title='&#92;lambda_i' class='latex' />.  It&#8217;s immediate that</p>
<p style="text-align:center;"><img src='http://s0.wp.com/latex.php?latex=S_k%28%5Clambda%29%3D%5Clambda_iS_%7Bk-1%2Ci%7D%2BS_%7Bk%2Ci%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='S_k(&#92;lambda)=&#92;lambda_iS_{k-1,i}+S_{k,i}' title='S_k(&#92;lambda)=&#92;lambda_iS_{k-1,i}+S_{k,i}' class='latex' /></p>
<p style="text-align:left;">Recall also the cones <img src='http://s0.wp.com/latex.php?latex=%5CGamma_k%3D%5C%7B%5Clambda%5Cin%5Cmathbb%7BR%7D%5En%7CS_1%28%5Clambda%29%3E+0%2C%5Ccdots%2CS_k%28%5Clambda%29%3E0%5C%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;Gamma_k=&#92;{&#92;lambda&#92;in&#92;mathbb{R}^n|S_1(&#92;lambda)&gt; 0,&#92;cdots,S_k(&#92;lambda)&gt;0&#92;}' title='&#92;Gamma_k=&#92;{&#92;lambda&#92;in&#92;mathbb{R}^n|S_1(&#92;lambda)&gt; 0,&#92;cdots,S_k(&#92;lambda)&gt;0&#92;}' class='latex' />.  We have <img src='http://s0.wp.com/latex.php?latex=%5CGamma_k%5Csupset+%5CGamma_%7Bk%2B1%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;Gamma_k&#92;supset &#92;Gamma_{k+1}' title='&#92;Gamma_k&#92;supset &#92;Gamma_{k+1}' class='latex' />.</p>
<p style="text-align:left;">We&#8217;re going to prove</p>
<p style="text-align:left;padding-left:30px;"><strong>Theorem.</strong> <img src='http://s0.wp.com/latex.php?latex=%5CGamma_k&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;Gamma_k' title='&#92;Gamma_k' class='latex' /> are convex.</p>
<p style="text-align:left;padding-left:30px;"><strong>Proof</strong>.  We&#8217;ll proceed by induction.  The base case, <img src='http://s0.wp.com/latex.php?latex=%5CGamma_1&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;Gamma_1' title='&#92;Gamma_1' class='latex' />, is clear, since <img src='http://s0.wp.com/latex.php?latex=%5CGamma_1&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;Gamma_1' title='&#92;Gamma_1' class='latex' /> is a half-space.</p>
<p style="text-align:left;padding-left:30px;">Now suppose that <img src='http://s0.wp.com/latex.php?latex=%5CGamma_k&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;Gamma_k' title='&#92;Gamma_k' class='latex' /> is convex.  Consider the functions on <img src='http://s0.wp.com/latex.php?latex=%5CGamma_%7Bl-1%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;Gamma_{l-1}' title='&#92;Gamma_{l-1}' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=Q_l%28%5Clambda%29%3D%5Cfrac%7BS_l%7D%7BS_%7Bl-1%7D%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='Q_l(&#92;lambda)=&#92;frac{S_l}{S_{l-1}}' title='Q_l(&#92;lambda)=&#92;frac{S_l}{S_{l-1}}' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=Q_%7Bl%2Ci%7D%3D%5Cfrac%7BS_%7Bl%2Ci%7D%7D%7BS_%7Bl-1%2Ci%7D%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='Q_{l,i}=&#92;frac{S_{l,i}}{S_{l-1,i}}' title='Q_{l,i}=&#92;frac{S_{l,i}}{S_{l-1,i}}' class='latex' />.  In fact, <img src='http://s0.wp.com/latex.php?latex=%5CGamma_l%3D%5C%7B%5Clambda%7C+Q_l%28%5Clambda%29%3E0%5C%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;Gamma_l=&#92;{&#92;lambda| Q_l(&#92;lambda)&gt;0&#92;}' title='&#92;Gamma_l=&#92;{&#92;lambda| Q_l(&#92;lambda)&gt;0&#92;}' class='latex' />, i.e. <img src='http://s0.wp.com/latex.php?latex=%5CGamma_%7Bl%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;Gamma_{l}' title='&#92;Gamma_{l}' class='latex' /> is the epigraph of <img src='http://s0.wp.com/latex.php?latex=Q_%7Bl%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='Q_{l}' title='Q_{l}' class='latex' />.<br />
Since we&#8217;ve assumed <img src='http://s0.wp.com/latex.php?latex=%5CGamma_k&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;Gamma_k' title='&#92;Gamma_k' class='latex' /> is convex, this means that convexity of <img src='http://s0.wp.com/latex.php?latex=%5CGamma_%7Bk%2B1%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;Gamma_{k+1}' title='&#92;Gamma_{k+1}' class='latex' /> is equivalent to <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B%5Cpartial%5E2%7D%7B%5Cpartial+%5Cxi%5E2%7DQ_%7Bk%2B1%7D%28%5Clambda%29%5Cleq+0&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;frac{&#92;partial^2}{&#92;partial &#92;xi^2}Q_{k+1}(&#92;lambda)&#92;leq 0' title='&#92;frac{&#92;partial^2}{&#92;partial &#92;xi^2}Q_{k+1}(&#92;lambda)&#92;leq 0' class='latex' />, where <img src='http://s0.wp.com/latex.php?latex=%5Cxi%5Cin%5Cmathbb%7BR%7D%5En%2C%5Clambda%5Cin%5CGamma_k&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;xi&#92;in&#92;mathbb{R}^n,&#92;lambda&#92;in&#92;Gamma_k' title='&#92;xi&#92;in&#92;mathbb{R}^n,&#92;lambda&#92;in&#92;Gamma_k' class='latex' />.</p>
<p style="text-align:left;padding-left:30px;">The relation <img src='http://s0.wp.com/latex.php?latex=S_%7Bk%2B1%7D%3D%5Clambda_iS_%7Bk%2Ci%7D%2BS_%7Bk%2B1%2Ci%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='S_{k+1}=&#92;lambda_iS_{k,i}+S_{k+1,i}' title='S_{k+1}=&#92;lambda_iS_{k,i}+S_{k+1,i}' class='latex' /> implies</p>
<p style="text-align:center;padding-left:30px;"><img src='http://s0.wp.com/latex.php?latex=%5Clambda_i%2BQ_%7Bk%2Ci%7D%3D%5Cfrac%7BS_k%7D%7BS_%7Bk-1%2Ci%7D%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;lambda_i+Q_{k,i}=&#92;frac{S_k}{S_{k-1,i}}' title='&#92;lambda_i+Q_{k,i}=&#92;frac{S_k}{S_{k-1,i}}' class='latex' /></p>
<p style="text-align:left;padding-left:30px;">and</p>
<p style="text-align:center;padding-left:30px;"><img src='http://s0.wp.com/latex.php?latex=%5Csum_i%5Clambda_i%5E2+S_%7Bk-1%2Ci%7D%3DHS_k-%28k%2B1%29S_%7Bk%2B1%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;sum_i&#92;lambda_i^2 S_{k-1,i}=HS_k-(k+1)S_{k+1}' title='&#92;sum_i&#92;lambda_i^2 S_{k-1,i}=HS_k-(k+1)S_{k+1}' class='latex' /></p>
<p style="text-align:left;padding-left:30px;">Dividing this last identity through by <img src='http://s0.wp.com/latex.php?latex=S_k&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='S_k' title='S_k' class='latex' />, we have</p>
<p style="text-align:center;padding-left:30px;"><img src='http://s0.wp.com/latex.php?latex=%28k%2B1%29Q_%7Bk%2B1%7D%3D%5Csum_i%5Clambda_i-%5Clambda_i%5E2%5Cfrac%7BS_%7Bk-1%2Ci%7D%7D%7BS_k%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='(k+1)Q_{k+1}=&#92;sum_i&#92;lambda_i-&#92;lambda_i^2&#92;frac{S_{k-1,i}}{S_k}' title='(k+1)Q_{k+1}=&#92;sum_i&#92;lambda_i-&#92;lambda_i^2&#92;frac{S_{k-1,i}}{S_k}' class='latex' /><br />
<img src='http://s0.wp.com/latex.php?latex=%3D%5Csum_i%5Clambda_i-%5Clambda_i%5E2%5Cfrac%7BS_%7Bk-1%2Ci%7D%7D%7BS_%7Bk%2Ci%7D%2B%5Clambda_iS_%7Bk-1%2Ci%7D%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='=&#92;sum_i&#92;lambda_i-&#92;lambda_i^2&#92;frac{S_{k-1,i}}{S_{k,i}+&#92;lambda_iS_{k-1,i}}' title='=&#92;sum_i&#92;lambda_i-&#92;lambda_i^2&#92;frac{S_{k-1,i}}{S_{k,i}+&#92;lambda_iS_{k-1,i}}' class='latex' /><br />
<img src='http://s0.wp.com/latex.php?latex=%3D+%5Csum_i%5Clambda_i-%5Cfrac%7B%5Clambda_i%5E2%7D%7B%5Clambda_i%2BQ_%7Bk%2Ci%7D%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='= &#92;sum_i&#92;lambda_i-&#92;frac{&#92;lambda_i^2}{&#92;lambda_i+Q_{k,i}}' title='= &#92;sum_i&#92;lambda_i-&#92;frac{&#92;lambda_i^2}{&#92;lambda_i+Q_{k,i}}' class='latex' /></p>
<p style="text-align:left;padding-left:30px;">So that the function <img src='http://s0.wp.com/latex.php?latex=Q_%7Bk%2B1%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='Q_{k+1}' title='Q_{k+1}' class='latex' />, whose concavity we&#8217;d like to establish, can be written in terms of the functions <img src='http://s0.wp.com/latex.php?latex=Q_%7Bk%2Ci%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='Q_{k,i}' title='Q_{k,i}' class='latex' />.</p>
<p style="text-align:left;padding-left:30px;">Now <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B%5Cpartial%5E2%7D%7B%5Cpartial+%5Cxi%5E2%7D%28Q_%7Bk%2Ci%7D%29%28%5Clambda%29%3D%5Cfrac%7B%5Cpartial%5E2%7D%7B%5Cpartial+%5Coverline%7B%5Cxi%7D%5E2%7DQ_%7Bk%7D%28%5Coverline%7B%5Clambda%7D%29&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;frac{&#92;partial^2}{&#92;partial &#92;xi^2}(Q_{k,i})(&#92;lambda)=&#92;frac{&#92;partial^2}{&#92;partial &#92;overline{&#92;xi}^2}Q_{k}(&#92;overline{&#92;lambda})' title='&#92;frac{&#92;partial^2}{&#92;partial &#92;xi^2}(Q_{k,i})(&#92;lambda)=&#92;frac{&#92;partial^2}{&#92;partial &#92;overline{&#92;xi}^2}Q_{k}(&#92;overline{&#92;lambda})' class='latex' />, where the bar means setting the ith component to zero.  It&#8217;s easy to check that <img src='http://s0.wp.com/latex.php?latex=%5Coverline%5Clambda%5Cin%5CGamma_%7Bk-1%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;overline&#92;lambda&#92;in&#92;Gamma_{k-1}' title='&#92;overline&#92;lambda&#92;in&#92;Gamma_{k-1}' class='latex' />, and by our inductive hypothesis, every second derivative of <img src='http://s0.wp.com/latex.php?latex=Q_k&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='Q_k' title='Q_k' class='latex' /> is nonpositive on this set.  So we have <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B%5Cpartial%5E2%7D%7B%5Cpartial+%5Cxi%5E2%7D%28Q_%7Bk%2Ci%7D%29%28%5Clambda%29%5Cleq+0&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;frac{&#92;partial^2}{&#92;partial &#92;xi^2}(Q_{k,i})(&#92;lambda)&#92;leq 0' title='&#92;frac{&#92;partial^2}{&#92;partial &#92;xi^2}(Q_{k,i})(&#92;lambda)&#92;leq 0' class='latex' />, i.e. <img src='http://s0.wp.com/latex.php?latex=Q_%7Bk%2Ci%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='Q_{k,i}' title='Q_{k,i}' class='latex' /> is concave on <img src='http://s0.wp.com/latex.php?latex=%5CGamma_k&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;Gamma_k' title='&#92;Gamma_k' class='latex' />.</p>
<p style="text-align:left;padding-left:30px;">The claim is now that the concavity of <img src='http://s0.wp.com/latex.php?latex=Q_%7Bk%2Ci%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='Q_{k,i}' title='Q_{k,i}' class='latex' /> implies the concavity of <img src='http://s0.wp.com/latex.php?latex=%5Clambda_i-%5Cfrac%7B%5Clambda_i%5E2%7D%7B%5Clambda_i%2BQ_%7Bk%2Ci%7D%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;lambda_i-&#92;frac{&#92;lambda_i^2}{&#92;lambda_i+Q_{k,i}}' title='&#92;lambda_i-&#92;frac{&#92;lambda_i^2}{&#92;lambda_i+Q_{k,i}}' class='latex' />.  This follows from a computation, but you can kind of see what&#8217;s going on by noting that <img src='http://s0.wp.com/latex.php?latex=Q_%7Bk%2Ci%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='Q_{k,i}' title='Q_{k,i}' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Clambda_i%2BQ_%7Bk%2Ci%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;lambda_i+Q_{k,i}' title='&#92;lambda_i+Q_{k,i}' class='latex' /> are degree-1 rational functions with nonpositive second derivatives.</p>
<p style="text-align:left;padding-left:30px;">Consider the 1-dimensional case.  A degree-1 rational function <img src='http://s0.wp.com/latex.php?latex=%5Cphi%28x%29&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;phi(x)' title='&#92;phi(x)' class='latex' /> is one which is asymptotic to a line; the nonpositive second derivative means the graph of <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' /> lies above the graph of the line.  For example, let&#8217;s let</p>
<p style="text-align:center;padding-left:30px;"><img src='http://s0.wp.com/latex.php?latex=%5Cphi%28x%29%3D%5Cfrac%7Bx%5E2%2B5x%7D%7Bx%2B3%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;phi(x)=&#92;frac{x^2+5x}{x+3}' title='&#92;phi(x)=&#92;frac{x^2+5x}{x+3}' class='latex' /></p>
<p style="text-align:left;padding-left:30px;">Then <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' /> is asymptotic to the line <img src='http://s0.wp.com/latex.php?latex=y%3Dx&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='y=x' title='y=x' class='latex' />, but since <img src='http://s0.wp.com/latex.php?latex=%5Cphi%28x%29%3Dx%5Cfrac%7Bx%2B5%7D%7Bx%2B3%7D%3Ex&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;phi(x)=x&#92;frac{x+5}{x+3}&gt;x' title='&#92;phi(x)=x&#92;frac{x+5}{x+3}&gt;x' class='latex' />, we have that the second derivative is nonpositive everywhere.  Here&#8217;s the graph of <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' />:</p>
<p style="text-align:center;padding-left:30px;"><a href="http://thecooper.files.wordpress.com/2008/06/phi.jpg"><img class="size-medium wp-image-42 aligncenter" src="http://thecooper.files.wordpress.com/2008/06/phi.jpg?w=461&#038;h=256" alt="" width="461" height="256" /></a></p>
<p style="text-align:left;padding-left:30px;">Now consider what happens when we take the function <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bx%5E2%7D%7B%5Cphi%7Bx%7D%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;frac{x^2}{&#92;phi{x}}' title='&#92;frac{x^2}{&#92;phi{x}}' class='latex' />, analogous to <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B%5Clambda_i%5E2%7D%7B%5Clambda_i%2BQ_%7Bk%2Ci%7D%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;frac{&#92;lambda_i^2}{&#92;lambda_i+Q_{k,i}}' title='&#92;frac{&#92;lambda_i^2}{&#92;lambda_i+Q_{k,i}}' class='latex' />.  In our example, we have <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bx%5E2%7D%7B%5Cphi%7Bx%7D%7D%3Dx%5Cfrac%7Bx%2B3%7D%7Bx%2B5%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;frac{x^2}{&#92;phi{x}}=x&#92;frac{x+3}{x+5}' title='&#92;frac{x^2}{&#92;phi{x}}=x&#92;frac{x+3}{x+5}' class='latex' />.  This function, you may notice, is also asymptotic to <img src='http://s0.wp.com/latex.php?latex=y%3Dx&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='y=x' title='y=x' class='latex' />, but it&#8217;s asymptotic to it from below, and its second derivative is <em>nonnegative</em>.</p>
<p style="padding-left:30px;text-align:center;"><a href="http://thecooper.files.wordpress.com/2008/06/phi2.jpg"><img class="size-medium wp-image-44 aligncenter" src="http://thecooper.files.wordpress.com/2008/06/phi2.jpg?w=458&#038;h=229" alt="" width="458" height="229" /></a></p>
<p style="text-align:left;padding-left:30px;">But the function we&#8217;re interested in is <img src='http://s0.wp.com/latex.php?latex=%5Clambda_i-%5Cfrac%7B%5Clambda_i%5E2%7D%7B%5Clambda_i%2BQ_%7Bk%2Ci%7D%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;lambda_i-&#92;frac{&#92;lambda_i^2}{&#92;lambda_i+Q_{k,i}}' title='&#92;lambda_i-&#92;frac{&#92;lambda_i^2}{&#92;lambda_i+Q_{k,i}}' class='latex' />.  Actually we&#8217;re interested in its second derivative, which means the linear term <img src='http://s0.wp.com/latex.php?latex=%5Clambda_i&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;lambda_i' title='&#92;lambda_i' class='latex' /> doesn&#8217;t matter, so we can discard it, and consider <img src='http://s0.wp.com/latex.php?latex=-%5Cfrac%7B%5Clambda_i%5E2%7D%7B%5Clambda_i%2BQ_%7Bk%2Ci%7D%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='-&#92;frac{&#92;lambda_i^2}{&#92;lambda_i+Q_{k,i}}' title='-&#92;frac{&#92;lambda_i^2}{&#92;lambda_i+Q_{k,i}}' class='latex' />, which is analogous to <img src='http://s0.wp.com/latex.php?latex=-%5Cfrac%7Bx%5E2%7D%7B%5Cphi%28x%29%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='-&#92;frac{x^2}{&#92;phi(x)}' title='-&#92;frac{x^2}{&#92;phi(x)}' class='latex' />, whose graph looks like</p>
<p style="text-align:center;padding-left:30px;"><a href="http://thecooper.files.wordpress.com/2008/06/phi3.jpg"><img class="size-medium wp-image-45 aligncenter" src="http://thecooper.files.wordpress.com/2008/06/phi3.jpg?w=467&#038;h=220" alt="" width="467" height="220" /></a></p>
<p style="text-align:left;padding-left:30px;">The relevant fact about this graph is that it has the same concavity as the original <img src='http://s0.wp.com/latex.php?latex=%5Cphi&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;phi' title='&#92;phi' class='latex' />!</p>
<p style="text-align:left;padding-left:30px;">So concavity of <img src='http://s0.wp.com/latex.php?latex=Q_%7Bk%2Ci%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='Q_{k,i}' title='Q_{k,i}' class='latex' />, which we have by the inductive hypothesis that <img src='http://s0.wp.com/latex.php?latex=%5CGamma_k&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;Gamma_k' title='&#92;Gamma_k' class='latex' /> is convex, is enough to show that each <img src='http://s0.wp.com/latex.php?latex=%5Clambda_i-%5Cfrac%7B%5Clambda_i%5E2%7D%7B%5Clambda_i%2BQ_%7Bk%2Ci%7D%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;lambda_i-&#92;frac{&#92;lambda_i^2}{&#92;lambda_i+Q_{k,i}}' title='&#92;lambda_i-&#92;frac{&#92;lambda_i^2}{&#92;lambda_i+Q_{k,i}}' class='latex' /> is concave, hence <img src='http://s0.wp.com/latex.php?latex=Q_%7Bk%2B1%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='Q_{k+1}' title='Q_{k+1}' class='latex' /> is the sum of concave functions, hence itself concave.  But this implies <img src='http://s0.wp.com/latex.php?latex=%5CGamma_%7Bk%2B1%7D&amp;bg=ffffff&amp;fg=1c1c1c&amp;s=0' alt='&#92;Gamma_{k+1}' title='&#92;Gamma_{k+1}' class='latex' /> is convex, which completes the induction.</p>
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