change notation and integrate by parts

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Tricki

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From Gowers: the Tricki is now open for business.

Written by thecooper

16 April 2009 at 3:02 pm

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why I am a nerd

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I have a project I’m saving for when I get old and grey and unable to do real math anymore.  Let me tell you about it.

My adviser, and many other folks besides, seem to have major beef with proof by contradiction.  It works, but it doesn’t advance the field.  Digging into a proof by contradiction, you’re not going to find a useful object to study.

But I find proofs by contradiction fascinating, and they feel quite natural to me somehow.  So I want to write a book of them.  More specifically, I want to see how many standard and/or famous proofs by contradiction can be interestingly tweaked into the ur-contradiction 0=1.   I’ll call it Conjectures on the One-Element Field.

Most blow-up arguments (like Sesum’s that I just posted about) fall into this category, as do a lot of index-theory arguments (the Hairy Ball Theorem needs its own chapter, I think).  The trick is to make the 0=1 part flow from the rest the proof, and not to be too obvious and artificial about it.

Written by thecooper

14 February 2009 at 12:30 am

scalar curvature blowup at first singular time

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I just figured out that Šešum’s proof that Ric\rightarrow \infty at a Ricci flow singularity in fact works, with a slight modification, to prove that R\rightarrow \infty at these singularities as well.

To get the proof to work in this case, I note that an inequality like (1-\epsilon)g(t_0)\leq g(t)\leq (1+\epsilon)g(t_0) is how one establishes Glickenstein’s Lemma.  If |Ric|\leq C, this inequality is immediate since \partial_t g=-2Ric.

However, we can still get such an inequality even if Ric isn’t bounded.  First note that, for the rescaled flows g_k(t)=Q_kg(t_k+\frac{t}{\sqrt{Q_k}}), we have a uniform Ricci bound |Ric_k|\leq 1.  So for each k we can choose t close enough to t_0 that

(1-\epsilon)g_k(t_0)\leq g_k(t)\leq (1+\epsilon)g_k(t_0)

Here ‘close enough’ is independent of k.  Then, using the definition of g_k, we see that

(1-\epsilon)g(t_k+\frac{t_0}{\sqrt{Q_k}})\leq g(t_k+\frac{t}{\sqrt{Q_k}})\leq (1+\epsilon)g(t_k+\frac{t_0}{\sqrt{Q_k}})

So if we want to prove, for any s and s_0, (1-\epsilon)g(s_0)\leq g(s)\leq (1+\epsilon)g(s_0), we just have to write s_0=t_k+\frac{t_0}{\sqrt{Q_k}}, s=t_k+\frac{t}{\sqrt{Q_k}}, which can clearly be done.  In fact we just have to find one such t_k.  So we get a Glickenstein’s Lemma for a flow with merely R bounded.

The rest of the proof works just fine, because in the limit we still get \overline{R}=0, hence by the evolution equation

\partial_tR=\Delta R+ |Ric|^2

we see that \overline{Ric}\equiv 0.

Written by thecooper

4 February 2009 at 1:07 am

Posted in moderate, ricci flow

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Huisken and Sinestrari 2008 – II

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I already gave the broad outline of Huisken and Sinestrari’s 2008 paper; I left out several big chunks that make the whole thing work.

Recall that we’re dealing with a family of 2-convex hypersurfaces evolving via mean curvature flow.  We’ll assume uniform 2-convexity, i.e. \lambda_1+\lambda_2\geq \alpha H for some \alpha>0.

I won’t go into the analytic work, but we need to use it.  There are two analytic results we need:

Cylindrical Estimate. For any \eta>0, there exists C(\eta) also depending on \alpha and the diameter of the initial hypersurface, so that along the flow

|A|^2-\frac{1}{n-1}H^2\leq \eta H^2+C(\eta)

I call this a cylindrical estimate because the quantity |A|^2-\frac{1}{n-1}H^2 vanishes on a cylinder, and when \lambda_1 is small it measures the sum of the squares of the differences of the higher eigenvalues.

Harnack Estimate. For any h,k\in \mathbb{N}, there exist C_1,C_2 >0 also depending on \alpha, the initial diameter, so that along the flow

|\partial_t^h\nabla^kA|\leq C_1 |A|^{2k+4h}+C_2

One first establishes these estimates for the smooth flow, and it’s rather easy to see that the surgery procedure doesn’t affect the constants, since surgery involves replacing approximate cylinders with approximate spheres.

Recall that the surgery procedure relies upon finding Hamilton necks–that is, regions of  the hypersurface that are approximate round cylinders.  In fact we want to do better than finding a region which looks like a cylinder at one time; we want to find regions that shrink like cylinders under the flow.

Definition. We call the spacetime region \Omega\subset M\times [a,b] an (\epsilon, k, L,\theta) shrinking neck if

  • The final time-slice \Omega_b is a Hamilton neck  \epsilon-close to a round neck in C^k.  Call the approximate radius of this neck r_b.
  • \Omega_t is (\epsilon,k) close to r(t)\Omega_b, where r(t) is the radius of a round cylinder at time t, which shrinks to radius r_b at time b.
  • b-a=r_b^2\theta, and each neck has length r_bL.

All of the singularity analysis resides in the following theorem:

Neck Detection Lemma. Let \epsilon, k, L,\theta be constants as above.  There exist constants \eta^*, H^* depending on \epsilon, k, L,\theta, \alpha, and the initial diameter, so that if any (p_0,t_0) satisfies:

  1. H(p_0,t_0)\geq H^* and \frac{\lambda_1}{H}(p_0,t_0)\leq \eta^*
  2. The parabolic neighbourhood P(p_0,t_0,L,\theta)=B_{g(t_0)}(p_0,\frac{n-1}{H(p_0)}L)\times [t_0-(\frac{n-1}{H(p_0)})^2\theta,t_0] doesn’t contain any points affect by a previous surgery.

then P(p_0,t_0,L-1,\frac{\theta}{2}) is an (\epsilon, k, L-1,\frac{\theta}{2})-shrinking neck.

To prove this theorem, we are going to argue by contradiction, using a blow-up argument.

Proof of the Neck Detection Lemma.  If the theorem is not true, we may take a sequence of flows, \{M(t)_j\} each of which contains a point (p_j,t_j) so that H(p_j,t_j)\rightarrow\infty, \frac{\lambda_1}{H}(p_j,t_j)}\rightarrow 0 and each parabolic neighbourhood P_j is unaffected by surgery, and so that none of them has P(p_j,t_j,L-1,\frac{\theta}{2}) as a shrinking neck.

Rescale and translate each of the flows: to get \tilde{M}_j(t)=H(p_j,t_j)[M_j(t_j+\frac{t}{H(p_j,t_j)})-p_j] so that \tilde{H}_j(0,0)=1.  The parabolic neighbourhoods all  rescale to the same \tilde{P}=\tilde{P}_j=P(0,0,L,\theta).

Tracing the Harnack estimate,  we get a Harnack estimate for H, so that the \tilde{H}_j are bounded uniformly on \tilde{P}.  Then the cylindrical estimate says that \tilde{A}_j are uniformly bounded in \tilde{P}.

Then the Harnack estimate says that in fact all derivatives of $latex\tilde{A}_j$ are uniformly bounded in \tilde{P}.  So according to the Arzela-Ascoli theorem, there is a limit flow \tilde{M}, with convergence in C^{k}(P(0,0,L-1,\frac{\theta}{2})) where k is the control we have on the derivatives during surgery.

Consider the properties of \tilde{M}. We have \tilde{H}(0,0)=1, \frac{\tilde{\lambda}_1}{\tilde{H}}(0,0)=0, |\tilde{A}|^2\leq \frac{1}{n-1}\tilde{H}^2.

Now \tilde{\lambda_1}\geq 0,  and \lambda_1 satisfies a parabolic equation, so achieving its minimum at an interior point means in fact \tilde{\lambda}_1\equiv 0.  Then |\tilde{A}|^2-\frac{1}{n-1}\tilde{H}^2=\sum_{1<i<j}(\tilde{\lambda}_1-\tilde{\lambda}_j)^2\geq 0.  So in fact \tilde{A} has a zero eigenvalue and all other eigenvalues equal.

The evolution equation for the quantity |A|^2-\frac{1}{n-1}H^2 (which we have just proved is identically zero) has a term involving |\nabla A|, so we see that \nabla A\equiv 0, i.e. A is covariant constant.  A rigidity theorem of Lawson says that this characterises cylinders.

Thus \tilde{M} is a shrinking cylinder on \tilde{P}.  So the sequence \tilde{M}_j\cap P(0,0,L-1,\frac{\theta}{2}) is approaching a shrinking cylinder, hence for large enough j, \tilde{P}_j is a shrinking neck.  But \tilde{P}_j is just a rescaling of P_j.  So P_j is a shrinking neck, in contradiction to our assumption.

Written by thecooper

1 February 2009 at 3:31 pm

Ricci blowup at first singular time

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The major analytic task in geometric flows is to understand the structure of singularities.   The first step toward understanding singularities and their development under the flow is a theorem like:

Characterisation of Ricci Flow Singularities.  Suppose \{g(t)\} is a Ricci flow, defined up to time T<\infty.  Assume T is maximal.  Then we have |\max Rm(t)|\rightarrow\infty, where Rm is the Riemann tensor.

That is to say, what goes wrong at a Ricci flow singularity is the curvature tensor.  We could restate the theorem as its contrapositive:

Characterisation of When the Flow Can Be Extended. Suppose that up to time t_0<\infty, we have a bound |\max Rm|\leq C<\infty.  Then the Ricci flow can be extended past t_0.

But of course the curvature tensor is a big nasty gadget, which is none too easy to understand.  We want something easier to check than “Are my curvatures all bounded?”.  Šešum proved that, in fact, one need only look at the trace of the Riemann tensor, which is the Ricci tensor:

Better Characterisation of Ricci Flow Singularities. As above, let T<\infty be the first singular time of a Ricci flow.  Then |\max Ric(t)|\rightarrow\infty.

This is somewhat remarkable, because the Ricci tensor interacts weirdly with Ricci flow.  For example, the condition Ric\geq K is not preserved under the flow.  Yet somehow the Ricci tensor carries the information about when singularities occur.  Proof under the fold.

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Written by thecooper

31 January 2009 at 4:58 pm

Huisken and Sinestrari 2008 – I

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This is essentially the talk I prepared for my comprehensive exam.  It’s a bit more detailed because, unlike in real life, there are no time limits on blogs.

The smooth mean curvature flow is a family of embeddings F_t:M^n\rightarrow R^{n+1} satisfying \frac{\partial F}{\partial t}=\overline{H}=-H\nu, that is, moving by its mean curvature.  For our purposes, we will consider M closed (compact without boundary).  I’ll be fairly cavalier about identifying the embedding F_t with its image M_t.

Now H=tr(A)=g^{ij}(\partial_i\partial_jF\cdot\nu), and we may take normal coordinates so that g_{ij}=\delta_{ij} and \partial_i\partial_jF is a normal vector.  In these coordinates, then, H=\sum_i \partial_i^2F.  So we may write \partial_t F=\Delta F, and think of the mean curvature flow as the heat equation for hypersurfaces.  In particular, the flow is parabolic, so we get maximum and comparison principles, as well as local existence and uniqueness.

As in the case of Ricci flow, mean curvature flow exhibits finite-time singularity development.  To see this, let M be any compact hypersurface.  Then M is contained in the interior of some sphere S, of radius R.  Now S collapses with radius r(t)=\sqrt{R^2-2nt}.  By the comparison principle, the flow starting at M stays inside the region bounded by r(t); in particular M develops a singularity before time t=\frac{R^2}{2n}. Sometimes, the singularity \{M_t\} achieves is collapse to a point, as in the case of the sphere.  We have

Huisken 1984. Suppose M is uniformly convex, i.e. \lambda_i\geq \alpha>0 where \lambda_i are the principal curvatures.  Then M is isotopic to a round sphere, with the isotopy given by a rescaled flow.

What happens when we relax the convexity assumption?  We say a hypersurface is 2-convex if \lambda_1+\lambda_2>0, where \lambda_1\leq\lambda_2\leq\cdots\leq\lambda_n are the principal curvatures.  This is equivalent to there being at most one negative principal curvature, which is also the smallest.

Huisken-Sinestrari 2008.  Suppose M is closed and 2-convex.  Then M is diffeomorphic to \#_k S^{n-1}\times S^1, i.e. the boundary of a handlebody.  Moreover the flow detects the connect sums.

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Written by thecooper

30 January 2009 at 3:25 am

proving sup bounds using Lp bounds and iteration

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Sorry for the break.  Got a lot on my plate.

A trick that’s come up a lot in my recent readings is using an L^p bound to get a bound on the supremum of some function.  The trivial case is what happens when \int f^p \leq C where the constant C is independent of p; then we just use the fact that the sup norm is the limit of the L^p norms.  But what if the constant C depends on p, and in fact blows up as p blows up?  Turns out all is not lost.

I’ll use the main theorem from Huisken 1984 as an example, though the same trick is used in Hamilton 1982 and Huisken-Sinestrari 1999.   The theorem is

Theorem. Suppose M is a closed convex hypersurface.  Then there exist constants C_0<\infty,\delta>0 such that \frac{|A|^2}{H^2}-\frac{1}{n}\leq CH^{-\delta} along a mean curvature flow starting from M.

The way to prove this is to consider the function f=f_\delta=H^{\delta-2}(|A|^2-\frac{1}{n}H^2) and try to prove that for some choice of \delta, it’s bounded.  Clearly the function is bounded at each time, but we need to keep the bounds from blowing up as we approach the first singular time.

There is an important fact we’re going to use about the function f.  It can absorb powers of H; that is, for any integer m, we have H^mf_\delta^p=f_\gamma^{p} for \gamma=O(p^{-\frac{1}{2}}).  Thus if we prove a L^p bound for f, we get L^p bounds for H^{\frac{m}{p}}f as well.

Now with a lot of tinkering (which is the hard part of the paper, and is different for different geometric assumptions), you can show that

Lemma.  There is a constant D so that if p is large and \delta=O(p^{-\frac{1}{2}}), we have \int f_\delta^p\leq D.

Now we want to consider the function v=v_k=(f-k)_+^\frac{p}{2}.  Notice that v_k^2 and f^p differ only by a constant.  Using the evolution equation for f, we can show without much fuss that

\frac{d}{dt}\int v_k^2+\int |\nabla v_k|^2\leq \delta p\int H^2f^p

Now we use the Michael-Simon Sobolev inequality (\int g^\frac{n}{n-1})^{\frac{n-1}{n}}\leq C(n)(\int |\nabla g|+\int Hg) with g=v_k^{\frac{2(n-1)}{n-2}} and the Holder inequality to get

(\int v_k^\frac{2n}{n-2})^\frac{n-2}{n}\leq C(\int|\nabla v_k|^2+(\int H^n)^\frac{2}{n}(\int v_k^\frac{2n}{n-2})^\frac{n-2}{n}

where all integrals are taken over the support of v_k, i.e. the region where f\geq k.  Notice that the left-hand side occurs on the right as well.

Now H^n \leq H^n f^p k^{-p} on the support of v_k, so we have \int H^n\leq k^{-p}D, where D is the sup bound.  So we have

\frac{d}{dt}\int v_k^2+D'(\int v_k^\frac{2n}{n-2})^\frac{n-2}{n}\leq \delta p\int H^2 f^p

Now integrate both sides in t to get

\int_{M_T} v_k^2-\int_{M_0}v_k^2+D'\int_0^T(\int v_k^\frac{2n}{n-2})^\frac{n-2}{n}\leq \delta p\int_0^T\int H^2 f^p

and choose k so large that f\geq k everywhere on M_0.  In particular,

D'\int_0^T(\int v_k^\frac{2n}{n-2})^\frac{n-2}{n}\leq \delta p\int_0^T\int H^2 f^p

So we can estimate integrals of v_k by integrals of H^2f^p.  Some more Holder and interpolation inequalities give

(\int v_k^{2q})^\frac{1}{q}\leq D'\delta p\int\int H^2 f^p

and using Holder again (stupidly this time–just pull a power of the volume out), this becomes

\int v_k^2\leq D'\delta p ||A(k)||^{2-\frac{1}{q}-\frac{1}{r}}(\int\int H^{2r} f^{pr})^\frac{1}{r}

where ||A(k)|| is the space-time volume of the support of v_k.  Now if h>k, we have |h-k|^p\leq v_k^2, so we get that

|h-k|^p||A(h)||\leq DD'\delta p ||A(k)||^{2-\frac{1}{q}-\frac{1}{r}}

which is a sort of decay estimate on the function k \mapsto ||A(k)||.  If we choose r big enough that the exponent on the RHS is greater than 1, this estimate says that if ||A(k)|| is small, ||A(h)|| has to be much smaller.  So the volume ||A(k)|| is decaying pretty fast. More specifically,

Stampacchia’s Lemma. Suppose \phi is a nonincreasing real function, which satisfies for all h>k,

|h-k|^\alpha \phi(h)\leq C\phi(k)^\gamma

where C,\alpha>0 and \gamma>1.  Then there is a number d<\infty with \phi(d)=0.

Thus we get a number k_0 for which ||A(k_0)||=0, that is, for which f\leq k_0 on the entire flow.

Written by thecooper

4 September 2008 at 5:39 pm

for Megan especially

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This article talks about the sort of math one can use to compare fossils (or living creatures), and the benefits that making said comparisons rigorous can have.

via Ars Mathematica

Written by thecooper

17 July 2008 at 11:58 am

Posted in mathematisation, nonmath posts

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fuzzy sets and God

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It’s been a while. Teaching does that. But back to the game.

Many times presuppositionalist apologists will bring up the nice crispness of logic and its unexplained utility for understanding the world as proof that God exists. There’s rationality out there, they say, which means there must be some intelligence, much like the rationality in our own heads is a product of intelligence.

I don’t find this convincing in the least, but I bring it up because today I came across an argument for the existence of God which takes the opposite tack, namely an appeal to fuzzy logic.

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Written by thecooper

17 July 2008 at 11:42 am

Huisken and Sinestrari 1999, pt. 4

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So I think I figured out basically what’s going on with those cones \Gamma_k. We needed them to be convex, so we could apply Hamilton’s maximum principle for systems.

Recall that the elementary symmetric polynomials on \mathbb{R}^n are defined by

S_k(\lambda)=\sum_{i_1<\cdots<i_k}\lambda_{i_1}\cdots\lambda_{i_k}

If we let S_{k,i} denote the polynomial formed by omitting from S_k without the terms involving \lambda_i. It’s immediate that

S_k(\lambda)=\lambda_iS_{k-1,i}+S_{k,i}

Recall also the cones \Gamma_k=\{\lambda\in\mathbb{R}^n|S_1(\lambda)> 0,\cdots,S_k(\lambda)>0\}. We have \Gamma_k\supset \Gamma_{k+1}.

We’re going to prove

Theorem. \Gamma_k are convex.

Proof. We’ll proceed by induction. The base case, \Gamma_1, is clear, since \Gamma_1 is a half-space.

Now suppose that \Gamma_k is convex. Consider the functions on \Gamma_{l-1}, Q_l(\lambda)=\frac{S_l}{S_{l-1}}, Q_{l,i}=\frac{S_{l,i}}{S_{l-1,i}}. In fact, \Gamma_l=\{\lambda| Q_l(\lambda)>0\}, i.e. \Gamma_{l} is the epigraph of Q_{l}.
Since we’ve assumed \Gamma_k is convex, this means that convexity of \Gamma_{k+1} is equivalent to \frac{\partial^2}{\partial \xi^2}Q_{k+1}(\lambda)\leq 0, where \xi\in\mathbb{R}^n,\lambda\in\Gamma_k.

The relation S_{k+1}=\lambda_iS_{k,i}+S_{k+1,i} implies

\lambda_i+Q_{k,i}=\frac{S_k}{S_{k-1,i}}

and

\sum_i\lambda_i^2 S_{k-1,i}=HS_k-(k+1)S_{k+1}

Dividing this last identity through by S_k, we have

(k+1)Q_{k+1}=\sum_i\lambda_i-\lambda_i^2\frac{S_{k-1,i}}{S_k}
=\sum_i\lambda_i-\lambda_i^2\frac{S_{k-1,i}}{S_{k,i}+\lambda_iS_{k-1,i}}
= \sum_i\lambda_i-\frac{\lambda_i^2}{\lambda_i+Q_{k,i}}

So that the function Q_{k+1}, whose concavity we’d like to establish, can be written in terms of the functions Q_{k,i}.

Now \frac{\partial^2}{\partial \xi^2}(Q_{k,i})(\lambda)=\frac{\partial^2}{\partial \overline{\xi}^2}Q_{k}(\overline{\lambda}), where the bar means setting the ith component to zero. It’s easy to check that \overline\lambda\in\Gamma_{k-1}, and by our inductive hypothesis, every second derivative of Q_k is nonpositive on this set. So we have \frac{\partial^2}{\partial \xi^2}(Q_{k,i})(\lambda)\leq 0, i.e. Q_{k,i} is concave on \Gamma_k.

The claim is now that the concavity of Q_{k,i} implies the concavity of \lambda_i-\frac{\lambda_i^2}{\lambda_i+Q_{k,i}}. This follows from a computation, but you can kind of see what’s going on by noting that Q_{k,i} and \lambda_i+Q_{k,i} are degree-1 rational functions with nonpositive second derivatives.

Consider the 1-dimensional case. A degree-1 rational function \phi(x) is one which is asymptotic to a line; the nonpositive second derivative means the graph of \phi lies above the graph of the line. For example, let’s let

\phi(x)=\frac{x^2+5x}{x+3}

Then \phi is asymptotic to the line y=x, but since \phi(x)=x\frac{x+5}{x+3}>x, we have that the second derivative is nonpositive everywhere. Here’s the graph of \phi:

Now consider what happens when we take the function \frac{x^2}{\phi{x}}, analogous to \frac{\lambda_i^2}{\lambda_i+Q_{k,i}}. In our example, we have \frac{x^2}{\phi{x}}=x\frac{x+3}{x+5}. This function, you may notice, is also asymptotic to y=x, but it’s asymptotic to it from below, and its second derivative is nonnegative.

But the function we’re interested in is \lambda_i-\frac{\lambda_i^2}{\lambda_i+Q_{k,i}}. Actually we’re interested in its second derivative, which means the linear term \lambda_i doesn’t matter, so we can discard it, and consider -\frac{\lambda_i^2}{\lambda_i+Q_{k,i}}, which is analogous to -\frac{x^2}{\phi(x)}, whose graph looks like

The relevant fact about this graph is that it has the same concavity as the original \phi!

So concavity of Q_{k,i}, which we have by the inductive hypothesis that \Gamma_k is convex, is enough to show that each \lambda_i-\frac{\lambda_i^2}{\lambda_i+Q_{k,i}} is concave, hence Q_{k+1} is the sum of concave functions, hence itself concave. But this implies \Gamma_{k+1} is convex, which completes the induction.

Written by thecooper

28 June 2008 at 12:54 am